According to Wittgenstein's Finite Rule Paradox every finite sequence of numbers can be a described in infinitely many ways and so can be continued any of these ways - some simple, some complicated but all equally valid. Conversely, it is possible to find a rule such that any number of your choice can be the next one.
The simplest rule for the given sequence of numbers is Un = 5*n + 3.
The nth term is 7n-5 and so the 6th term will be 37
It is T(n) = n2 + 4*n + 2.
The pattern is: +11, +15, +19, +23, +27 (4n+7) So, the next number would be: (4*6 + 7) = 24 + 7 = +31 Therefore, the answer is: 105 + 31 = 136
Well, start with any decimals u have, like 0.36. that is first. then the single digits, like 1, which is next. then 13, 23 and finally 33. since 13 is lower then 23, which is lower then 33. so the order is 0.36, 1, 13, 23, 33.
23/100 13/20
Un = 5n - 2
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
It is: 5n+3 and so the next term is 28
The 'n'th term is [ 13 + 5n ].
18,23,28,33,... #1 is 18 #2 is 23 A difference of '5' Hence we can write '5n + x = 18 Where 'n' equals '1' Hence 5(1) + x = 18 5 + x = 18 Hence x = 18 - 5 = 13 So nth term is 5n + 13 NB Verification; does it work for the 4th term 5(4)+ 13 = 20 + 13 = 33 Which is true from above list.
14+9n
It is: 10n-7 and so the next term is 43
58
A simple answer, based on a linear rule is U(n) = 5n - 23 for n = 1, 2, 3, ...
All you have to do is add 5 each time(x+5) It's 43
Assuming the pattern would continue: 25, 24, 23, 22, 21, 20, 19, 18, 17, 16, 15, 14, 13...