As stated the question is impossible since such a rectangle cannot exist. The area of a rectangle is measured in square units of length not in centimetres.
Assuming the area is 49 square centimetres, the perimeter can be any number greater than 28 cm.
Consider a rectangle of length L cm where L is any number greater than 7.
Let W = 49/L cm be the width of the rectangle.
Then the area of the rectangle is L*W = L*49/L = 49 cm.
The perimeter can be increased by making the rectangle longer and thinner. And this can be done without any maximum limit. L can be 100 cm, 1 kilometre, 1 million kilometres, anything! Try it and see - and the perimeter is 2*(L+W)
For a square, the area is the length of a side squared and the perimeter is 4 times the length. If the area is 49, then the length of a side is 7. The perimeter is then 4 times 7, or 28.
7*7 = 49 square cm
Perimeter = 154 mm = 15.4 cmArea = 1,372 mm2 = 13.72 cm2
I think this means we have a shape with a perimeter 39cm and we are asked what is the smallest area. It is a rectangle of length 19.5cm and width zero. Or perhaps it should read area 49 cm squared., what is the smallest periimeter. A circle with 49=pi x r2. Then perimeter=pi x 2r
It can be infinitely large. Consider a rectangle of length A cm where A ≥ 7 cm. And let its width be B = 49/A cm. Then its area is always A*B cm2 = A*49/A cm2 = 49 cm2. Let A = 10 cm, B = 4.9 cm so perimeter = 29.8 cm or A = 100 cm, B = 0.49 cm, perimeter = 200.98 cm or A = 1000 cm, B = 0.049 cm, perimeter = 2000.98 cm By making the rectangle infinitesimally thin and infinitely long, its perimeter can be increased without limit.
For a square, the area is the length of a side squared and the perimeter is 4 times the length. If the area is 49, then the length of a side is 7. The perimeter is then 4 times 7, or 28.
28 centimeters, if its a square. If it's a rectangle you can't solve.A=s249=72side=7P=4sP=4 x 7P=28
7*7 = 49 square cm
Perimeter = 154 mm = 15.4 cmArea = 1,372 mm2 = 13.72 cm2
Area of a square can be calculated using the formula A = a^2, where "a" is the length of a side of the square. Its perimeter is P = 4*a. 49 = a^2 => a = 7cm P = 4*7 = 28cm The perimeter of the square is 28cm.
I think this means we have a shape with a perimeter 39cm and we are asked what is the smallest area. It is a rectangle of length 19.5cm and width zero. Or perhaps it should read area 49 cm squared., what is the smallest periimeter. A circle with 49=pi x r2. Then perimeter=pi x 2r
It can be infinitely large. Consider a rectangle of length A cm where A ≥ 7 cm. And let its width be B = 49/A cm. Then its area is always A*B cm2 = A*49/A cm2 = 49 cm2. Let A = 10 cm, B = 4.9 cm so perimeter = 29.8 cm or A = 100 cm, B = 0.49 cm, perimeter = 200.98 cm or A = 1000 cm, B = 0.049 cm, perimeter = 2000.98 cm By making the rectangle infinitesimally thin and infinitely long, its perimeter can be increased without limit.
28 meters It would be a square because A = L x W so 49 = 7 x W and the width is 7. Its perimeter is 4*7 = 28 meters.
The perimeter will be 28.
The area of rectangle is : 56.0
A square with are area of 64 square centimeters has a perimeter of 32 centimeters, since there are four sides, each 8 centimeters in length.
The area of a square with perimeter 28cm is: 49 cm2