Pentagon has 5 sides
Regular => each side 9cm
=> perimeter = 5 x 9cm = 45cm
any 2-D shape could have a perimeter of 9cm. One example is a square with sides of 9/4 cm.
Area 51.
This is not an equilateral triangle.
No. The sum of the lengths of any two sides of a triangle must be greater that the third. Here 6 + 9 = 15, not > 15.
Assuming no fractional dimensions, least possible area would be a rectangle measuring 1cm x 9cm. Area increases to a maximum of 25 sq cm when shape is square, ie 5cm x 5cm.
Perimeter = sum of the lengths of sides = 5* 7 cm = 35 cm
It would be 63cm. There are 7 sides and each side is 9cm so 7 times 9 is 63.
any 2-D shape could have a perimeter of 9cm. One example is a square with sides of 9/4 cm.
Perimeter = 6cm + 6cm + 9cm + 9cm = 30cm
Well, honey, making a shape with a perimeter of 9cm is as easy as pie. You could have a triangle with sides measuring 3cm, 3cm, and 3cm. Or you could have a rectangle with sides measuring 2cm and 2.5cm. Just remember, the perimeter is the sum of all the sides, so get those measuring tapes out and get creative!
An arbitrary large number is the answer for anyrectangle, up to that with a length of 9cm, and 0cm as the width will have a perimeter of 18cm.Similarly, any rectangle up to that with sides 0cm long, and a width of 9cm will have your 18cm perimeter.
it is 81cm
The perimeter of a parallelogram can be calculated by adding the lengths of all sides. Since the parallelogram has two pairs of equal sides, the formula for the perimeter is ( P = 2(a + b) ), where ( a ) and ( b ) are the lengths of the sides. In this case, ( a = 14 ) cm and ( b = 9 ) cm. Thus, the perimeter is ( P = 2(14 + 9) = 2(23) = 46 ) cm.
if you have a box that is 9cm long and 3cm wide then you would say width + length + width + length because the side opposite from 3cm is also 3cm and the side opposite 9cm is also 9cm. so you would add: 9cm+9cm+3cm+3cm = 24cm if you have a box that is 9cm long and 3cm wide then you would say width + length + width + length because the side opposite from 3cm is also 3cm and the side opposite 9cm is also 9cm. so you would add: 9cm+9cm+3cm+3cm = 24cm
9cm + 5cm + 9cm + 5cm = 28cm
ok if the perimeter is 36cm and it is a square then you know all four sides are equal 36cm / 4sides = 9cm for each side A = L * W ( both the length and width are 9cm because each side is equal ) A = 9cm * 9cm A = 81cm2
Think about two numbers whose multiplication is 9 or simply think about the factors of 9. Factors of 9 are 3x3 Now see perimeter of rectangle is 2 times sum of length and breadth. Perimeter of rectangle is 4 times side. 2 and 4 are of the factors of 9. So the figure cannot be rectangle or square. Perimeter of triangle= Sum of all sides 9 = 1+3+5 =9 Hence it is possible to have a triangle with perimeter 9cm as there are various numbers whose addition could be 9. So the figure could be triangle.