(4x^4 - x³ + 17x² + 11x + 4) ÷ (4x + 3) = x³ - x² + 5x - 1 remainder 7.
Do the division via long division, looking at the highest power of x in the dividend:
_________________x³ ___- x²_ + 5x - 1
________-----------------------------------
4x + 3 | 4x^4 - x³ + 17x² + 11x + 4
_________4x^4 + 3x³ _____________________ ← x³(4x + 3); x³ in the quotient
_________--------------
_______________- 4x³ + 17x² ______________ ← subtract and bring down next term (+ 17x²)
_______________ -4x³ __ -3x² ______________ ← -x²(4x + 3); - x² in the quotient
_______________---------------
______________________ 20x² + 11x ________ ← subtract and bring down the next term (+ 11x)
______________________ 20x² + 15x ________ ← 5x(4x + 3); + 5x in the quotient
______________________ --------------
______________________________ -4x + 4 ____ ← subtract and bring down the next term (+ 4)
______________________________ -4x - 3 _____ ← -1(4x + 3); -1 in the quotient
______________________________ --------
___________________________________ 7 ______ ← subtract; no more terms to bring down, this is remainder.
2
P squared = P*P. When divided by P, the equation becomes (P*P/P, and the answer is "P".
4
1
X2 (X squared)
6x3+29x2-40x-42 divided by 6x+5 Quotient: x2+4x-10 Remainder: 8
The quotient works out as: x^2+2x+4 and there is a remainder of -3
x3+3x2+6x+1 divided by x+1 Quotient: x2+2x+4 Remaider: -3
Dividend: 6x^3 +29^2 -40x -42 Divisor: 6x +5 Quotient: x^2 +4x -10 Remainder: 8
When any number is divided by itself, the quotient is always ' 1 ' exactly.
The quotient of a reciprocal would equal the numerator squared divided by the denominator squared. i.e. (x/y)/(y/x) = x2/y2
1
Dividend: 6x^3+29x^2-40x-42 Divisor: 6x+5 Quotient: x^2+4x-10 Remainder: 8
Dividend: 4x^4 -x^3 +17x^2 +11x +4 Divisor: 4x +3 Quotient: x^3 -x^2 +5x -1 Remainder: 7
its 5 squared divided by the sum of 28 to the power of ten. -maths teacher
you divided and you are .
2x4 - 9x3 + 13x2 - 15x + 9 = 2x4 - 6x3 - 3x3 + 9x2 + 4x2 - 12x - 3x + 9 = 2x3(x - 3) - 3x2(x - 3) + 4x(x - 3) - 3(x - 3) = (x - 3)*(2x3 - 3x2 + 4x - 3) So the quotient is (2x3 - 3x2 + 4x - 3) and the remainder is 0.