24,25,26
10 and 12
Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.
The numbers are -16 and -15.
99 = 9*11
24,25,26
The numbers are 18 and 20.
10 and 12
224 x 226
The numbers are 8 and 9.
Its 28 and 29.
Find two consecutive numbers with the value of 4160
For the product to be zero, one of the numbers must be 0. So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.
They are are 7 and 8.
62 & 61
28 and 29
27 and 28