4, -1236, -108 is not a geometric system.
If you want to ask questions about the "following", then I suggest that you make sure that there is something that is following.
Formula for the nth term of general geometric sequence tn = t1 x r(n - 1) For n = 2, we have: t2 = t1 x r(2 - 1) t2 = t1r substitute 11.304 for t2, and 2.512 for t1 into the formula; 11.304 = 2.512r r = 4.5 Check:
Well, well, well, look who's getting fancy with geometric sequences! When the ratio between consecutive terms is "r," each term is found by multiplying the previous term by "r." So, in simpler terms, if you have a sequence like 2, 4, 8, 16, the ratio between consecutive terms is 2. Math can be sassy too, honey!
The formula for height depends on the context. There is no simple formula for the height of a person. Formulae for the height of a geometric shape depends on what information about the shape is given.
The given sequence is an arithmetic sequence with a common difference of -4. To find the nth term formula, we first determine the first term, which is 100. The nth term formula for an arithmetic sequence is given by: a_n = a_1 + (n-1)d, where a_n is the nth term, a_1 is the first term, n is the term number, and d is the common difference. Therefore, the nth term formula for this sequence is a_n = 100 - 4(n-1) or a_n = 104 - 4n.
what is the recursive formula for this geometric sequence?
arithmetic sequence * * * * * A recursive formula can produce arithmetic, geometric or other sequences. For example, for n = 1, 2, 3, ...: u0 = 2, un = un-1 + 5 is an arithmetic sequence. u0 = 2, un = un-1 * 5 is a geometric sequence. u0 = 0, un = un-1 + n is the sequence of triangular numbers. u0 = 0, un = un-1 + n(n+1)/2 is the sequence of perfect squares. u0 = 1, u1 = 1, un+1 = un-1 + un is the Fibonacci sequence.
un = u0*rn for n = 1,2,3, ... where r is the constant multiple.
-7
It look like a Fibonacci sequence seeded by t1 = 2 and t2 = 1. After that the recursive formula is simply tn+1 = tn-1 + tn.
If you want to ask questions about the "following", then I suggest that you make sure that there is something that is following.
In this case, 22 would have the value of 11.
The sequence 1, 4, 13, 40, 121 can be described by a recursive formula. The recursive relationship can be expressed as ( a_n = 3a_{n-1} + 1 ) for ( n \geq 2 ), with the initial condition ( a_1 = 1 ). This means each term is generated by multiplying the previous term by 3 and then adding 1.
The formula to find the sum of a geometric sequence is adding a + ar + ar2 + ar3 + ar4. The sum, to n terms, is given byS(n) = a*(1 - r^n)/(1 - r) or, equivalently, a*(r^n - 1)/(r - 1)
The given sequence is a geometric sequence where each term is multiplied by 2 to get the next term. The first term (a) is 4, and the common ratio (r) is 2. The nth term of a geometric sequence can be found using the formula ( a_n = a \cdot r^{(n-1)} ). Therefore, the nth term of this sequence is ( 4 \cdot 2^{(n-1)} ).
In order to answer the question is is necessary to know what the explicit formula was. But, since you have not bothered to provide that information, the answer is .
The recursive formula for a sequence typically defines each term based on previous terms. For a sequence denoted as ( A(n) ), ( B(n) ), and ( C(n) ), a common recursive approach might be: ( A(n) = A(n-1) + B(n-1) ) ( B(n) = B(n-1) + C(n-1) ) ( C(n) = C(n-1) + A(n-1) ) These formulas assume initial values are provided for ( A(0) ), ( B(0) ), and ( C(0) ). Adjustments can be made based on the specific context or properties of the sequence.