b= 4.5
Wiki User
∙ 15y ago8b + 11 - 3b = 2b + 2 5b + 11 = 2b + 2 5b - 2b = 2 - 11 3b = -9 b = -3
b over the square root of 5 The square root of 5b squared is 5b, and the simplified form of the square root of 125 is 5 root 5. The 5s then cancel out leaving b over the square root of 5.
a^(2)- 2ab - 15b^(2) When the first term has a coefficient of '1' (a^(2)), then look at the third term. It is '15'. So we need two numbers that multiply to '15' and 'add/subtract'to '2'. They are 3. & 5. So writing up our brackets ( a 5b)(a 3b) Which signs??? We note from the quadraic , that '15' is negative(-) . So the brackets need one positive(+) and one negative(-) Since the middle term is also negative(-) , then the larger numerical number takes the negative. Hence ( a - 5b)(a + 3b) Done!!!!
No. 7b - 2b = 5b
-b+5b-2b=2b
3a + (3b - 2a) + 5b =3a + 3b - 2a + 5b =(3a - 2a) + (3b + 5b) =a + 8b
add like terms: 3a -2a -5b + 6b +3b - 7b = a -3b
5b plus 5-3b-7 is 2b-2.
We can combine the like terms. So the b2 can be combined with the 2b2 to give 3b2. Likewise the 3b plus the -5b gives -2b.Therefore, b2 + 3b - 5b + 2b2 = 3b2 - 2b.
They are like terms and can be added simply as 5b
here is how you go about solving it first write down the question 3b+4+5b-1 then change arrangement so that it looks like this 3b+5b+4-1 then solve 8b+3
5b + 11 - 2b = 3b + 11
8b + 11 - 3b = 2b + 2 5b + 11 = 2b + 2 5b - 2b = 2 - 11 3b = -9 b = -3
3a - 2b
8b -2a
5b - 3 - 2b = 6b - 3 3b - 3 = 6b - 3 3b - 6b = 3 - 3 b = 0
5+3b? :3