0
What else can I help you with?
What are the lengths of the missing sides of a 30-60-90 triangle if the longer leg of the triangle is 18 centimeter?
The longest side of the triangle will always be opposite the largest angle, which is 90° in this case. We can use the sine law to work out the other sides with that: sin(90°) / 18 = sin(60°) / x = sin(30°) / y 1/18 = sin(60°) / x x = 18 sin(60°) x = 18√3 / 2 x = 9√3 1/18 = sin(30°) / y y = 18 sin(30°) y = 9 So the triangle has a sides of 9 and 9√3, with a hypotenuse of 18
Cos 60 equals and sin 60 equals?
cos60= 1/2 sin60=1.732/2
What is the sin of 105 degrees?
sin 105 = sin (60+45) = sin60cos45 + cos60sin45sin 105 = ((sqrt(3)/2)((sqrt(2)/2)) + ((1/2)((sqrt(2)/2)))sin 105 = (sqrt(6) + sqrt(2)) / 4
What is the resultant of a 30 unit and 60 unit vector inclined to each other at 60 degrees?
Suppose the 30 unit vector is acting horizontally. Then the 60 unit vector has a horizontal component of 60*cos(60) units and a vertical component of 60*sin(60) units. So total horizontal = 30 + 60*cos(60) = 60 units total vertical = 60*sin(60)= 51.96 units. Then magnitude of resultant = sqrt(602 + 51.962) = sqrt(6300) = 79.37 units (approx). And direction = tan-1(51.96/60) = 40.89 degrees (from the 30 unit vector).
What is the area of an equilateral triangle when its perimeter is 22.5 cm?
Area = 0.5*7.52*sin(60 degrees) = 24.357 square cm rounded to 3 dp.
Why is sine 30 the same as cosine of 60?
sin(30) = sin(90 - 60) = sin(90)*cos(60) - cos(90)*sin(60) = 1*cos(60) - 0*sin(60) = cos(60).
What is the ratio for sin 120 degrees?
The sine of 120 degrees can be found using the unit circle. It is equivalent to sin(180° - 60°), which gives sin(120°) = sin(60°). Since sin(60°) is √3/2, the ratio for sin 120 degrees is √3/2.
The shorter leg of a 30-60-90 degree triangle is 6 what is the length of the other leg?
Use the Sine rule. If L is the length of the longer leg, then L/sin(60) = 6/sin(30) So that L = 6*sin(60)/sin(30) = 12*sin(60) = 12*sqrt(3)/2 = 10.39 units.
What is the tangent of 60 degrees?
Tan(60) = Sin(60)/ Cos(60) Sin(60) = sqrt(3)/2 Cos(60) = 1/2 Hence Sin(60) / Cos(60) = [sqrt(3) / 2] / [1/2} => sqrt(3) / 2 X 2/1 sqrt(3) Hence Tan(60) = sqrt(3) = Numerically = 1.732050808....
What are the ratios of the length of the longer leg of a 30-60-90 triangle to the length of its hypotenuse?
The longer leg is opposite the 60 deg angle. Suppose A = 60 deg, C = 90 deg and a and c are the corresponding sides. Then, by the sine rule a/c = sin(A)/sin(C) a/c = sin(60)/sin(90) = sqrt(3)/2
How will the value of sin 35 determine?
to find sin 35 here we take the angle = x=15 then 3x=45 , 4x=60 then 4x-3x=60-45 then by putting sin on rhs we will get cos 35 and sin 35 hope it helped you
Find the value of sin 300 degrees?
sin 300 = -sin 60 = -sqrt(3)/2 you can get this because using the unit circle.
What is the cofunction of sin 30 degree?
cos 60
A hypotenuse of a 30-60-90 triangle has a length of 13 what is the length is the side opposite of the 60 degree angle?
Use trigonometry and the sine ratio: sin = opp/hyp and when rearrange hyp*sin = opp 13*sin(60) = 11.25833025 or 11.26 units in length to 2 d.p.
What is the length of the side opposite the 60 angle if the hypotenuse is 17?
The length of the side opposite the 60° angle is about 14.72(sin 60°) = 0.866The length of the side opposite the 30° angle is 8.5(sin 30°) = 0.5
What is sin60?
The sine of 60 degrees, denoted as sin(60°), is equal to √3/2. This value arises from the properties of a 30-60-90 triangle, where the ratio of the lengths of the sides opposite the angles is well-defined. Therefore, sin(60°) is approximately 0.866.
Solve sin x square root of 3 by 2?
Do you mean sin(x)=sqrt(3)/2? IF so, look at at 30/60/90 triangle. We see the sin 60 degrees is square (root of 3)/2
