The longest side of the triangle will always be opposite the largest angle, which is 90° in this case. We can use the sine law to work out the other sides with that: sin(90°) / 18 = sin(60°) / x = sin(30°) / y 1/18 = sin(60°) / x x = 18 sin(60°) x = 18√3 / 2 x = 9√3 1/18 = sin(30°) / y y = 18 sin(30°) y = 9 So the triangle has a sides of 9 and 9√3, with a hypotenuse of 18
cos60= 1/2 sin60=1.732/2
sin 105 = sin (60+45) = sin60cos45 + cos60sin45sin 105 = ((sqrt(3)/2)((sqrt(2)/2)) + ((1/2)((sqrt(2)/2)))sin 105 = (sqrt(6) + sqrt(2)) / 4
Suppose the 30 unit vector is acting horizontally. Then the 60 unit vector has a horizontal component of 60*cos(60) units and a vertical component of 60*sin(60) units. So total horizontal = 30 + 60*cos(60) = 60 units total vertical = 60*sin(60)= 51.96 units. Then magnitude of resultant = sqrt(602 + 51.962) = sqrt(6300) = 79.37 units (approx). And direction = tan-1(51.96/60) = 40.89 degrees (from the 30 unit vector).
Area = 0.5*7.52*sin(60 degrees) = 24.357 square cm rounded to 3 dp.
sin(30) = sin(90 - 60) = sin(90)*cos(60) - cos(90)*sin(60) = 1*cos(60) - 0*sin(60) = cos(60).
Use the Sine rule. If L is the length of the longer leg, then L/sin(60) = 6/sin(30) So that L = 6*sin(60)/sin(30) = 12*sin(60) = 12*sqrt(3)/2 = 10.39 units.
The longer leg is opposite the 60 deg angle. Suppose A = 60 deg, C = 90 deg and a and c are the corresponding sides. Then, by the sine rule a/c = sin(A)/sin(C) a/c = sin(60)/sin(90) = sqrt(3)/2
to find sin 35 here we take the angle = x=15 then 3x=45 , 4x=60 then 4x-3x=60-45 then by putting sin on rhs we will get cos 35 and sin 35 hope it helped you
cos 60
sin 300 = -sin 60 = -sqrt(3)/2 you can get this because using the unit circle.
Use trigonometry and the sine ratio: sin = opp/hyp and when rearrange hyp*sin = opp 13*sin(60) = 11.25833025 or 11.26 units in length to 2 d.p.
The length of the side opposite the 60° angle is about 14.72(sin 60°) = 0.866The length of the side opposite the 30° angle is 8.5(sin 30°) = 0.5
Do you mean sin(x)=sqrt(3)/2? IF so, look at at 30/60/90 triangle. We see the sin 60 degrees is square (root of 3)/2
sin 480° is equal to sin 60°, which is sqrt(3)/2 or approximately 0.866.
The longest side of the triangle will always be opposite the largest angle, which is 90° in this case. We can use the sine law to work out the other sides with that: sin(90°) / 18 = sin(60°) / x = sin(30°) / y 1/18 = sin(60°) / x x = 18 sin(60°) x = 18√3 / 2 x = 9√3 1/18 = sin(30°) / y y = 18 sin(30°) y = 9 So the triangle has a sides of 9 and 9√3, with a hypotenuse of 18
square root 3/2