2x-7y=14 2x-14=7y from this equation the slope is 2/7
If: 2x-7y = 20 Then: y = 2/7x -20/7 which is now in slope-intercept form
If: 4x-7y-28 = 0 then y = 4/7x-4 whereas 4/7 is the slope and -4 is the y intercept
Point: (7, -5) Slope: -4/7 Equation: 7y = -4x-7
Points: (8, 8) and (1, 2) Slope: (8-2)/(8-1) = 6/7 Equation: y-8 = 6/7(x-8) => 7y-56 = 6x-48 => 7y = 6x-48+56 Slope intercept form: 7y = 6x+8
2x-7y=14 2x-14=7y from this equation the slope is 2/7
In order to find the slope of your line, we must first get it into y=mx+b.-9x-7y = 8-9x + 9x - 7y = 8- 7y = 9x + 8-7y/7 = 9x/7 + 8/7-y = 9x/7 + 8/7(-1) -y = 9x/7 + 8/7y = -9x/7 - 8/7The slope is -9/7 and the y-intercept is -8/7
Slope is found by this form. Y = mX + c ( m = slope ) - 5X - 7Y - 6 = 0 ( I assume this is what you mean ) - 7Y - 6 = 5X - 7Y = 5X + 6 Y = - 5/7X - 6/7 The slope would be in this instance, - 5/7 ----------
if: 6x - 7y = 10 then -7y = 10 - 6x y = 6x/7 - 10/7 The slope is now the coefficient of x, which is 6/7.
The slope intercept form is: y = mx + b 9x + 7y = 15 9x - 9x + 7y = 15 - 9x 7y = - 9x + 15 y = -(9/7)x + 15/7
If: 2x-7y = 20 Then: y = 2/7x -20/7 which is now in slope-intercept form
The simplest way is to rewrite the equation in the standard for: y = mx + c. Then the slope is m. 8x - 7y = 56 7y = 8x - 56 y = 8/7 * x - 8 So the slope is 8/7
Parallel lines have the same slope. -3x - 7y = -8; the slope = -(-3/-7) = -3/7. Thus any line with slope of -3/7 is parallel to -3x - 7y = -8. Exampes: -6x - 14y = 0 -3x - 7x = 2 etc.
-7y + 21 = 3x Add '7y' to both sides 21 = 3x + 7y Subtract '3x' from both sides 21 - 3x = 7y 'Swop around'. 7y = -3x + 21 Divide both sides by '7' y = -(3/7)x + 3 The slope of a straight line is the coefficient of 'x' In this case it is ' -3/7'.
8 over 7.
Slope of the given line is 3/7 So slope of perpendicular line is -7/3
Where an equation is presented in this form then convert it to the standard slope intercept format of y = mx + c. The value of m is the slope. 3x - 7y = 14 7y = 3x - 14 y = 3/7x - 2 The slope is therefore 3/7.