Points: (8, 8) and (1, 2)
Slope: (8-2)/(8-1) = 6/7
Equation: y-8 = 6/7(x-8) => 7y-56 = 6x-48 => 7y = 6x-48+56
Slope intercept form: 7y = 6x+8
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
y=13x
The equation in slope-intercept form would be y=-2x
please help
It works out in its general form as: 3x-4y-6 = 0
y = 2x + 1.
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
The straight line equation is: y = 2x
The standard form of the equation is 2x - y + 5 = 0
Slope-intercept form
33
y = x
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
y=13x
It is a straight line equation in the form of: y = x
i dont knows
UndefinedImproved Answer:-The straight line equation is: y = 2x