it should actually look like this- 5x - y = 11 sorry
anything with the same slope as that line which I'm guessing is 2Answer:You mean y=2x-11 ? If so, then a parallel line would be:y= 2x + (any number)
To find the equation of a line passing through two points, we first calculate the slope using the formula (y2 - y1) / (x2 - x1). Given the points (1, 11) and (-2, 2), the slope is (2 - 11) / (-2 - 1) = -9 / -3 = 3. Next, we use the point-slope form of a linear equation, y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line. Substituting (1, 11) as the point and 3 as the slope, we get the equation y - 11 = 3(x - 1). Simplifying, we get y = 3x + 8 as the equation of the line.
If you mean: (2, 13) and (-4, -11) then the slope is 4 and both equations will have the same slope of 4 but with different y intercepts
Points: (7, 0) and (0, 11) Slope: 0-11/7-0 = -11/7 Equation: y-0 = -11/7(x-7) => 7y = -11x+77 Equation: y-11 = -11/7(x-0) => 7y = -11x+77
Slope intercept form is y = mx + b. Point slope form is y - y1 = m(x - x1). Here is an example of changing slope-intercept form to point-slope form: Change y = 3x + 2 to point slope form: y = 3x + 2 Subtract 2 from each side: y -2 = 3x The equation y-2 = 3x is in point-slope form. It can be rewritten as y-2 = 3(x-0), showing that the line passes through the point (0,2), but is doesn't need to be. (The x1 and y1 represent one point on the line, it doesn't matter which one. Therefore, there are many different equations for the same line in point-slope form. For example, the equation y -2 = 3x is the same line as the equation y - 11 = 3(x - 3), which is the same line as the equation y + 4 = 3(x + 2).)
You are missing a - or + sign. The answer is 5/2 though. :)
The general equation os a straight line is u = mx + c Where 'm' is the slope and 'c' is the y0intercept. So for parallel lines the slope must be the same in both cases. So for a slope od '11' We can have y = 11x + 5 y = 11x - 8 A parallel lines. A special case. y = 11x + 3 y' = 11x' + 3 Are parallel lines AND co-linear.
0.96
If you mean y = 11x then the slope is 11
11
3x + y = 4 y = -3x + 4 (the slope is -3) The line that passes through the point (-3, -2) has a slope of -3, since it is parallel to the line with equation 3x + y = 4 (parallel lines have equal slopes). Using the slpoe -3 and the point (-3, -2) we find the equation of the required line such as (y - -2) = -3(x - -3) y + 2 = -3x - 9 y = -3x -11 3x + y = -11
y = 11x + 5 The slope/gradient of this equation is 11. The slope/gradient can easily been seen in a linear equation: it is simply the co-efficient of x
anything with the same slope as that line which I'm guessing is 2Answer:You mean y=2x-11 ? If so, then a parallel line would be:y= 2x + (any number)
anything with the same slope as that line which I'm guessing is 2Answer:You mean y=2x-11 ? If so, then a parallel line would be:y= 2x + (any number)
The equation of a parallel line is of the form 2x - y = c for some c. (-3, -11) is on this lime so 2*(-3) - (-11) = c -6 + 11 = c so that c = 5 and therefore, the equation is 2x - y = 5
1.67 or 1.667
Put the equation of the given line into slope-intercept form. The slope is then the coefficient of x. -5x + 8y = 27. 8y = 5x + 27 y = 5/8 x + 33/8.........so the slope of a parallel line is the same i.e. 5/8 Now use the standard slope-intercept equation , y = mx + c, where m is the slope and c is the y-intercept. Substituting the ordered pair values for x and y, and as m is known - this gives, -3 = 5/8(-7) + c : -3 = -43/8 + c : c = 13/8 The equation of the parallel line is thus, y = 5/8x + 13/8 and multiplying throughout by 8 produces an equivalent equation, 8y = 5x + 11