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The equation y=x-5, has a slope of "one". An equation in the form of y=mx+b has a slope of "m" and the y-intercept of "b".

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16y ago

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What is the slope of a line x equals 5?

X=5 is a vertical line, so it has no slope. When I say it has no slope, I don't mean the slope is 0, I mean the slope is nonexistent.


A line such as x equals 5 has what kind of slope?

Undefined slope.


What is a slope of the line y5?

If y = 5 then there is no slope because the line is parallel to the x axis


Find the slope what line 5y equals x plus 5?

After solving for y you will get y=1/5 x+1. The slope of this line is 1/5.


What is the slope of the line x equals a constant value?

A line with the equation:x = a constant valueis a vertical line. Examples of such a line are x = 3, x = 5, x = 10, x = -4.The slope of a vertical line is infinite.


What is the slope of the line that passes through 2 5 and -1 5?

Points: (2, 5) and (-1, 5) Slope: 0 and so therefore it has no slope but is a straight line parallel to the x axis


What is the slope of the line 5y minus x equals 10?

5y - x = 10 5y = x + 10 or y = x/5 + 2 This is now the equaltion of the line in the standard form and the slope of the line is the coefficieint of x that is, 1/5 or 0.2


Who A line has a slope of -5 and passes through 1 -1 Which is the equation of the line in point-slope form?

The point-slope form of a line's equation is given by (y - y_1 = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is a point on the line. Given the slope (m = -5) and the point ((1, -1)), the equation in point-slope form is (y + 1 = -5(x - 1)).


What is the point slope equation for the line that passes through the point 5 and 5?

To write the point-slope equation of a line that passes through the point (5, 5), you need a slope (m) as well. The point-slope form is given by the equation ( y - y_1 = m(x - x_1) ). If the slope is not provided, you can express the equation generically as ( y - 5 = m(x - 5) ), where ( m ) is the slope of the line. If you have a specific slope, you can substitute it into the equation.


What is the slope of a line that lies perpendicular to a line with a slope of 1 5?

The line perpendicular to a line with a slope of 1/5 has a slope of -5.


What is the slope-intercept form of the equation through negative 2 5 parallel to y equals a negative x subtract 1?

Since the line that passes through (-2, 5) it is parallel to the line with equation y = -x -1 and slope -1, then its slope is also -1, as parallel lines have the same slope.In order to write the point-slope form of that line, we use the slope m = -1 and the point (x1, y1) = (-2, 5), such as(y - y1) = m(x - x1)y - 5 = -1(x - -2)y - 5 = -1(x + 2)y - 5 = -x - 2 (solve for y to obtain the slope-intercept form of the equation of the line)y - 5 + 5 = -x + 5 - 2 (add 5 to both sides)y = -x + 3Thus, the slope-intercept form of the line that passes through (-2, 5) and parallel to the line with equation y = -x -1, is y = -x + 3.


What is the equation of a line with a slope of -1 and a y-intercept of -5?

The equation of the line is: y = -x-5