Points: (2, 5) and (-1, 5) Slope: 0 and so therefore it has no slope but is a straight line parallel to the x axis
Points: (3, 4) and (5, 4) Slope: (4-4)/(3-5) = 0 There is no slope and it is a straight line parallel to the x axis
9
If the slope is undefined, it is a vertical line. Therefore the equation is x=2.
x - 5 is not an equation, it is an expression. It cannot represent a line and so there is no question of any slope. Since x is a variable, it can take on infinitely many values, thus the value of x - 5 depends on x. If we impose a variable y which will represents all the values produced by x - 5, then we form a linear equation with 2 variables, y = x - 5. As we know, this is the slope-intercept form of an equation, y = mx + b. Thus, the slope is 1.
X=5 is a vertical line, so it has no slope. When I say it has no slope, I don't mean the slope is 0, I mean the slope is nonexistent.
Undefined slope.
If y = 5 then there is no slope because the line is parallel to the x axis
After solving for y you will get y=1/5 x+1. The slope of this line is 1/5.
A line with the equation:x = a constant valueis a vertical line. Examples of such a line are x = 3, x = 5, x = 10, x = -4.The slope of a vertical line is infinite.
Points: (2, 5) and (-1, 5) Slope: 0 and so therefore it has no slope but is a straight line parallel to the x axis
5y - x = 10 5y = x + 10 or y = x/5 + 2 This is now the equaltion of the line in the standard form and the slope of the line is the coefficieint of x that is, 1/5 or 0.2
Since the line that passes through (-2, 5) it is parallel to the line with equation y = -x -1 and slope -1, then its slope is also -1, as parallel lines have the same slope.In order to write the point-slope form of that line, we use the slope m = -1 and the point (x1, y1) = (-2, 5), such as(y - y1) = m(x - x1)y - 5 = -1(x - -2)y - 5 = -1(x + 2)y - 5 = -x - 2 (solve for y to obtain the slope-intercept form of the equation of the line)y - 5 + 5 = -x + 5 - 2 (add 5 to both sides)y = -x + 3Thus, the slope-intercept form of the line that passes through (-2, 5) and parallel to the line with equation y = -x -1, is y = -x + 3.
The line perpendicular to a line with a slope of 1/5 has a slope of -5.
A linear equation in the form y = mx + c has slope m The slope m' of a line perpendicular to a line with slope m is such that m'm = -1 → m' = -1/m 3x + 9y = 5 → 9y = -3x + 5 → y = (-3/9)x + 5/9 → y = -⅓x + 5/9 → its slope is -⅓ → perpendicular lines have slope m' = -1/(-⅓) = 3 → Every line perpendicular to 3x + 9y = 5 has slope 3.
The equation of the line is: y = -x-5
If they are perpendicular, the product of their slopes should be -1 -1*X = -1 X = 1 The other line has slope 1