A linear equation in the form y = mx + c has slope m
The slope m' of a line perpendicular to a line with slope m is such that m'm = -1 → m' = -1/m
3x + 9y = 5
→ 9y = -3x + 5
→ y = (-3/9)x + 5/9
→ y = -⅓x + 5/9
→ its slope is -⅓
→ perpendicular lines have slope m' = -1/(-⅓) = 3
→ Every line perpendicular to 3x + 9y = 5 has slope 3.
Slope of given line = -3 Therefore, slope of perpendicular = 1/3
For the line 2x + y = 8 , the slope equals ( -2 ) so the required slope of the line which is perpendicular to it is equal to (+1/2 )
The slope of the perpendicular to a line has a slope which is the negative reciprocal of the original line's slope.The negative reciprocal of x is -1/xSo in this case, where the slope is -2 the perpendicular line has the slope -1/(-2) or simply 1/2
line in data is y=-2X+6 The perpendicular line will have a slope of = +1/2 Note : m X m' = -1 , m= slope of line 1 ; m'= slope of perpendicular line to line 1
- 1/3
The slope of the perpendicular is -(1/2) .
Slope of given line = -3 Therefore, slope of perpendicular = 1/3
For the line 2x + y = 8 , the slope equals ( -2 ) so the required slope of the line which is perpendicular to it is equal to (+1/2 )
10 is.
The slope of the perpendicular to a line has a slope which is the negative reciprocal of the original line's slope.The negative reciprocal of x is -1/xSo in this case, where the slope is -2 the perpendicular line has the slope -1/(-2) or simply 1/2
45
It is: minus 1.25
line in data is y=-2X+6 The perpendicular line will have a slope of = +1/2 Note : m X m' = -1 , m= slope of line 1 ; m'= slope of perpendicular line to line 1
negative 1
It is: 1/5
If: y = 2/5x+10 then the perpendicular slope is -5/2x or -2.5x
A perpendicular line has the negative reciprocal of the slope. The perpendicular line has a slope of 1/2 y=1/2 + 3 The 3 or y-intercept can really be any number though.