If the line has a slope of 2, then the perpendicular line has a slope of -1/2. The slope of a perpendicular line is the negative reciprocal. Another example would be if the slope of a line is -1/4, then the slope of the perpendicular is 4.
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
Points: (-2, 3) and (1, 1) Slope: -2/3
1/4
The slope of the perpendicular is -(1/2) .
If a line has a slope m then a line perpendicular to it has a slope -1/m ( negative inverse). For example if a line has slope positive 2, its perpendicular has slope -1/2
Answer:-10/2=-5Solution:The relation between the line slope and it's perpendicular line slope is negative reciprocal, i.e.Slope of the line perpendicular = -1/Slope of the line= -1/(2/10)= -1 x 10/2= -10/2= -5
If the line has a slope of 2, then the perpendicular line has a slope of -1/2. The slope of a perpendicular line is the negative reciprocal. Another example would be if the slope of a line is -1/4, then the slope of the perpendicular is 4.
The line between the points (3, 4) and (2, 1) has: slope = change_in_y/change_in_x = (4 - 1)/(3 - 2) = 3/1 = 3
The slope of the perpendicular to a line has a slope which is the negative reciprocal of the original line's slope.The negative reciprocal of x is -1/xSo in this case, where the slope is -2 the perpendicular line has the slope -1/(-2) or simply 1/2
Points: (-1, 2) and (3, -1) Slope of line: -3/4
Perpendicular line = - 1/gradient= - 1/2/3= - 3/2
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
(0, 0) and (-2 -2) -2-0 divided by -2-0 which gives a slope of 1
-1/2 (APEX)
between points (x0, y0) and (x1, y1): slope = change_in_y/change_in_x → slope = (y1 - y0)/(x1 - x0) → slope = (3 - 0)/(1 - 2) = 3/(-1) = -3
1/2