If you mean points of (3, 9) and (-4, 2) then the slope of the line is 1
If you mean points of (3, 9) and (1, 3) then the slope is 3
If you mean points of (5, 8) and (3, 9) then the slope works out as -1/2
39
The factors of 39 are 1,3,13,39.
the answer is 39/100. It cannot be simplified more further.
If you mean points of (3, 9) and (1, 3) then the slope is 3
The slope is -9.
39
If you mean points of: (-5, -39) and (10, 84) then the slope works out as 41/5 which is the same as 8.2
39 APEX
To find the slope between the points (-20, -18) and (19, 5), use the slope formula: ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the values, we get ( m = \frac{5 - (-18)}{19 - (-20)} = \frac{5 + 18}{19 + 20} = \frac{23}{39} ). Therefore, the slope of the line connecting these two points is ( \frac{23}{39} ).
If you mean points of (5, 8) and (3, 9) then the slope works out as -1/2
To find the slope of the line that passes through the points (5, 8) and (3, 9), use the formula for slope ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Here, ( (x_1, y_1) = (5, 8) ) and ( (x_2, y_2) = (3, 9) ). Plugging in the values, we get ( m = \frac{9 - 8}{3 - 5} = \frac{1}{-2} = -\frac{1}{2} ). Thus, the slope of the line is (-\frac{1}{2}).
SMBC Theater - 2009 Slippery Slope 1-39 was released on: USA: 7 February 2010
A line with slope m and a point (x0, y0) on it has equation: y - y0 = m(x - x0) The slope of the tangent is perpendicular to the slope of the radius to the point (3, 2) The product of the slope of a line and a line perpendicular to it is -1. A circle with centre (X, Y) and radius r has equation: (x - X)² + (y - Y)² = r² For x² + 10x + y² - 2y - 39 = 0 and the point (3, 2): x² + 10x + y² - 2y - 39 = 0 → x² + 10x + (10/2)² - (10/2)² + y² - 2y + (2/2)² - (2/2)² - 39 = 0 → (x + 5)² - 25 + (y - 1)² - 1 - 39 = 0 → (x - -5)² + (y - 1)² = 65 → the circle has centre (-5, 1) and radius √65. The slope m' of the radius to (3, 2) from the centre of (-5, 1) is given by: slope = change_in_y / change_in_x → m' = (2 - 1) / (3 - -5) = 1/8 → slope m of the tangent is: mm' = -1 → m = -1/m → m = -1/(1/8) = -8 Thus the tangent has equation: y - 2 = -8(x - 3) → y - 2 = -8x + 24 → y + 8x = 26
39
Equation of circle: x^2 +10x +y^2 -2y -39 = 0 Completing the squares: (x+5)^2 +(y-1)^2 = 65 Center of circle: (-5, 1) Slope of radius: 1/8 Slope of tangent line: -8 Point of contact: (3, 2) Equation of tangent line: y-2 = -8(x-3) => y = -8x+26 Note that the tangent line meets the radius of the circle at right angles.