Using the quadratic equation formula: x = -5-/+ the square root of 7
Without an equality sign the given expression can't be classed as an equation but it can be simplified to: x-37
This is a simultaneous equation question. 4(3x+4y = 90) 3(4x-3y = -5) Multiply the top equation by 4 and the bottom equation by 3 then subtract the bottom equation from the top equation remembering that in maths a minus from a minus is equal to a plus. 12x+16y = 360 12x-9y = -15 And when subtracted: 0+25y = 375 Divide both sides of the equation by 25 to find the value of y: y = 15 Substitute 15 for y into the original equation to find the value of x: Solution: x = 10 and y = 15
x2 - 25 = 0 is x2 = 25 thus x = 5 or x = -5, only 2 real solutions
2x + 5 + 3x = 25 5x + 5 = 25 Subtract 5 from both sides: 5x = 20 Divide both sides by 5: x = 4
You can check an answer by substituting it into the equation. x - 17 = 11 25 - 17 = 11 8 = 11 Since this is not true, 25 is not the answer.
5r = 25 is a linear equation in one variable, r. The solution is r = 5.
It is a linear equation in x. It has a solution, which is x = -5
x - 8 = 17x = 25 (add 8 to both sides)
Using the quadratic equation formula: x = -5-/+ the square root of 7
If: 11x+25 = 7x+15 then there is only one solution and it is x = -2.5
For the equation x2- 10x - k equals 0, you can solve this by knowing that if there is only one solution then the discriminant b2 - 4ac must be equal to 0. In this equation, a is 1, b is 10 and c is k This equation becomes 100 - 4k equals 0, and k is 25.
It is an equation of: 5x+3 = 28 and its solution is x = 5 5 times x plus 3 equals 28. Subtract 3 from both sides of the equation. 5 times x equals 25. Divide both sides of the equation by 5. x equals 5. (stop)
34
Divide each side of the equation by 10 .
25
An equation where y = 81