5y-2y= 3y+2 5y-2y-3y= 2 0y= 2
Yes it is!
z = -4 x-5 y+2
x + 5y = 10 5y = -x + 10 y = -x/5 + 2 m = -1/5 or .2
(10, 2)
5y + 7 = 25y = -5y = -1
(-5, 2)
3x + 5y = -1 2x - 5y = 16 Add the two equations: 5x = 15 or x = 3 Substitute for x in the first equation: 3*3 + 5y = -1 15 + 5y = -1 5y = -10 so y = -10/5 = -2 The solution is (x, y) = (3, -2)
2x + 5y = 16 -2x - 3y = -14 2y = 2 y = 1 / x = 5.5 (5.5,1) or (5 1/2,1)
y=(-1) x=(2)
5y-2y= 3y+2 5y-2y-3y= 2 0y= 2
3
(2, 2)
7x + 5y 7(3) + 5(2) 21 + 10 = 31
Yes it is!
(2, 1)
3y+5.2=2-5y 8y=-3.2 y= -0.4