You just have to plug in numbers for x and plot it on a graph. You can't have a square root of a negative number, so the graph starts at 0 and moves to the right. You'll have to use a calculator to get the decimal approximation for some of y values. x=0, y=0 x=1, y=1 x=2, y= square root of 2 x=3, y=square root of 3 x=4, y=2 x=5, y=square root of 5 etc...
y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.
X^2 + Y^2 = 36 Y^2 = 36 - X^2 Y = (+/-)sqrt(36 - X^2) A circle. X = (+/-) 6 Y = (+/-) 6
y=x+1 there for answer is 2
It is y = x + 4
y = |x| - 2
Im assuming you are trying to come up with a y intercept equation for a graph. If that assumption is correct x = y^2 - 2 y^2 = x + 2 y = SQRT ( x + 2 )
Im assuming you are trying to come up with a y intercept equation for a graph. If that assumption is correct x = y^2 - 2 y^2 = x + 2 y = SQRT ( x + 2 )
y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.
X^2 + Y^2 = 36 Y^2 = 36 - X^2 Y = (+/-)sqrt(36 - X^2) A circle. X = (+/-) 6 Y = (+/-) 6
y=x+1 there for answer is 2
X - Y^2 = 1 - Y^2 = - X + 1 Y^2 = X - 1 Y = (+/-) sqrt(X - 1) now, X is represented as a function of Y. Function values are generally Y values.
x = +/- sqrt(y/3)
First, reflect the graph of y = x² in the x-axis (line y = 0) to obtain the graph of y = -x²; then second, shift it 3 units up to obtain the graph of y = -x² + 3.
The graph shifts downward (negative y) by 9 units.
3
Any graph in which there is at least one value of x for which there are more than one values of corresponding y. For example y = sqrt(x).
So 5 = (xy)^2 and x = 2.5. This means that 5 = (2.5y)^2. So sqrt(5)/2.5 = y when x = 2.5. Now if x = 9 then 5 = (9y)^2. So sqrt(5)/9 = y. This means that for any x in this relation y = sqrt(5)/x.