3y squared - 2y = 1
It is a quadratic expression and is (2y-1)(3y-4) when factored
If: 3x-2y = 1 Then: 9x^2 = (1+2y)^2 by squaring both sides If: 3x^2 -2y^2 +5 = 0 Then: 9x^2 = 6y^2 -15 by multiplying all terms by 3 So: 6y^2 -15 = 1+4y +4y^2 Transposing and collecting like terms: 2y^2 -16 -4y = 0 Divide all terms by two: y^2 -8 -2y = 0 Factorizing: (y-4)(y+2) = 0 => y = 4 or y = -2 Therefore solutions by substitution are: (3, 4) and (-1, -2)
x+2y = 2 2y = -x+2 y = -0.5x+1 Therefore the slope is -0.5 and the y intercept is 1
2y=4x+1 sp y=2x+1/2 so the slope or gradient is 2
2y + 1
2y^2+5y+2=(2y+1)(y+2)
11y(y - 1)(2y^2 + 2y - 1)
3y squared - 2y = 1
2(x - 1)(2x + y)
Equations: 3x-2y = 1 and 3x^2 -2y^2 +5 = 0 By combining the equations into one single quadratic equation and solving it the points of contact are made at (3, 4) and (-1, -2)
x^2 + x -x^2 +1 =x+1
(2y+1)(y−5)
104
2y + 7x + y-1?
If you mean: 2x^2 +2y^2 -8x -5y -1 = 0 making contact at (1, -1) Then the tangent equation in its general form works out as: 4x+9y+5 = 0
2y+8y2 can be factored to 2y(1+4y)