104
1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 = 1 + 1 + 1 + 1 + 1 + 1 = 5
1 squared (1x1) +3=4
8 + X SQUARED
The sum of two squares cannot be factored. It can be represented thus: X2 + y2 = (x + yi)(x - yi) In this expression, the i is the symbol for the imaginary number the square root of -1.
104
1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 = 1 + 1 + 1 + 1 + 1 + 1 = 5
(2y + 1) + (y^2 + 1) = 2y + 1 + y^2 + 1 = y^2 + 2y + 2
Because the letters can represent any sum not necessarily its only on a triangle where that happens the hypotenuse squared equals the sum of the other two sides squared added together like if a was 1 and b was two c could be three so 1+4 doesn't equal 9
1 squared plus 8 squared or 4 squared plus 7 squared
x[x+1] squared Simplified is, to my knowledge, x squared plus ( x + 1) squared
It is 1.
The question contains an expression but not an equation. An expression cannot be solved.
1 squared (1x1) +3=4
1 + cot2x = csc2x
1+32+52=41... The brackets go around the first part like this - (1+3)2+52=41 Because... 1+3=4 squared is 16, add that to 5 squared (25) equals 41.
the sum of 1 plus 9 is 10 because 1+9