It is an integer.
The sum of 2 consecutive numbers cannot be 118, because you cannot get an even number when you add an even and an odd number.
The next integer is 1101, but there is no next number.
a car going from stoplight to next intersection accelerates at a positive rate of velocity change
let x = 1st integer x + 1 = next consecutive integer x + x + 1 = 15 2x + 1 = 15 2x = 14 x = 7 x = 1 = 8
Descending (in a sequence) means that a the next number is "more negative" or "closer to negative infinity" or "less positive" or "further from positive infinity" or if n is a number in a sequence and n+1 is the next number then n/n+1 > 1
2.
The next odd integer after 40 is 41
n + 1
n-3
A consecutive positive integer is the next positive whole number following a given integer. For example, the consecutive positive integers after 5 would be 6, 7, 8, and so on.
2n + 2 = 2(n+1)
The greatest integer that is less than -4 is -5. -5 is next largest integer, even though it has the smallest absolute value for the set of number <-4. This is because the less negative a value is, the greater it is, even though it's numeric component '5' is not the largest.
The sum of 2 consecutive numbers cannot be 118, because you cannot get an even number when you add an even and an odd number.
Every integer is either even (divisible by 2) or odd (not divisible by 2). Since an even number plus 1 is odd and an odd number plus one is even, because 1 does not divide 2. We know (n + 4) is odd. The next integer is (n + 4 + 1) = (n + 5), because an odd number plus 1 is even, (n + 5) is even. The integer after (n + 5) is (n + 6), since (n + 5) we know is even, (n + 6) must be odd. Since (n + 6) is the smallest integer that is greater than (n + 4) and is odd, so (n + 6) is the next odd integer.
Let x = first even integer then x + 2 = next even integer sum: x + x + 2 = 624 2x + 2 = 624 2x = 622 x = 311 x + 2 = 313 NOTICE the values are ODD not EVEN so there is no solution
An even integer is a number that is a multiple of 2. If n is an even integer, the next consecutive even integers are n+2, n+4 and so on.
No. The positive integers are {1, 2, 3, 4, 5, ...}. They start at 1 (which is the least positive integer) and progress forever (to infinity). There is no end to the positive integers, so there is no greatest positive integer. Another way to look at it might be to think of any really large integer (a "counting" or "whole" number) and add one. That will create a "next bigger" large number. You can continue to do this infinitely many times.