2n + 2 = 2(n+1)
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Let the smallest integer be 2n, the next integer is 2n + 2, and the largest one is 2n + 4. Then, we have:2n + (2n + 2) = (2n + 4) + 164n + 2 = 2n + 202n = 18 the smallest integer2n + 2 = 18 + 2 = 20 the next one2n + 4 = 18 + 4 = 22 the largest integerCheck
In general mathematicians use n to signify any integer. On this basis 2n must be an even integer.But, are you sure it was a mathematician who wrote 2n ? There's no law about this.
246 and 248.Any even number can be written in the form 2n, for some integer n. The next consecutive integer is 2n + 2. These two numbers added together equal 494:2n + (2n + 2) = 494so4n + 2 = 4944n = 492n = 123so2n = 246 and 2n +2 = 248.
The answer depends on n. If n is an integer or half on integer then 2n is a whole number; if not, then it isn't.
An odd number can be written in the form '2n+1' where 'n' is an integer, and an even number can be written int the form '2n'. We can then write the sum of 2 odd numbers as: (2n+1) + (2m+1) * Combining and factoring out a 2, we arrive at: 2(n + m + 1) Since 'n' and 'm' are both integers, we know that the value contained int the '()' is also an integer. We can therefore rewrite this equation to be: 2n Which represents an even number as given previously. * 'm' is an integer