0
What is the sum of the product of a number k and 4 and a number m?
Wiki User
∙ 10y ago
(k x 4) + m = 4k + m
Just put the numbers together with the unknown for products, then put the other parts you need to add behind (think of grouping)
Wiki User
∙ 10y ago
Add your answer:
Earn +20 pts
How do you write the sum of a number k and 7?
k + 7
Fx equals x cubed plus 4?
x = ¼x^4 + 4x + k where k can be any number
The sum of two numbers is k Find the minimum value of the sum of their cubes?
1
What is the product of k and 6?
It is simply: 6k
The sum of the 10 binomial coefficients of the form C 9 k?
45
What is twice the sum of k and 4?
2(k+4)
The sum of a number k and 7?
k + 7
How do you write the sum of a number k and 7?
k + 7
What is a Number that is the product of a number?
If A is a prime, then the answer is A^k where k is any positive integer.
Is the sum of four even numbers always a multiple of 4?
No, the sum of four even numbers is not always a multiple of 4.. For example, 4 + 6 + 10 + 14 = 34 which is not a multiple of 4 If you include an "odd" number of even numbers which are not multiples of 4, then the total will not divide exactly by 4. In the above example 6 = 4 + 2, 10 = 4 + 4 + 2, and 14 = 4 + 4 + 4+ 2, and the total of the odd number of twos will not divide by 4 All multiples of 4 are the product of 2 with another even number: (Let a multiple of 4 be 4k. But 4 = 2 x 2, so 4k = (2 x 2)k = 2 x 2k and 2k is an even number for all k.) Let the four even numbers be 2k, 2m, 2n, 2p for some k, m, n, p. Then their sum is 2k + 2m + 2n + 2p = 2 (k + m + n + p) = 2q where q = k + m + n + p. k, m, n & p can be even or odd. If one, or three, of these is odd, then their sum, q, is odd. To be a multiple of 4 the sum k + m + n + p (= q) must be even. If it is odd, then twice it will not be a multiple of 4. For example, if k = 1, m = 2, n = 3, p = 5, then the four even numbers are 2 x 1 = 2, 2 x 2 = 4, 2 x 3 = 6, 2 x 5 = 10 and their sum is 2 x (1 + 2 + 3 + 5) = 2 x 11 = 22 which is not a multiple of 4.
Algorithm for to find sum of individual digits of a positive integer?
enter the number whose digits are to be added num is the given value num=0! k=num%10 sum=sum=k k=num/10 num=k print the sum of the digits
6 divided by the sum of 4 times x and 5 times k?
6 divided by the sum of 4 times x and 5 times k is equal to 6 times the reciprocal of (4x + 5k).
How do you write the sum of all even numbers from 2-15 using D O Until Loop?
17
A triangle has sides 3 4 and k If k is an integer what values of k are possible?
The sum of any two sides of a triangle is greater than the third side. So, 3+4>k, that is k<7 Also, 3+k>4 so that k>1 So 1 < k < 7
When 3.5times a number is divided by 4 the quotient is 70find the number?
Let the number be k. According to the question the equation is; (3.5 * k) / 4 = 70 (3.5 * k) =280 k = 280 / 3.5 =80 Therefore the number is 80.
Write a program to find the sum of squares of the given number?
#include<stdio.h> int main() { int count,i,j,k,n,*a,sum=0; printf("Enter the value of 'n':"); scanf("%d",&n); a=malloc(n*sizeof(int)); for(i=1;i<=n;i++) { count=0; j=1; while(j<=i) { if(i%j==0 && i!=2) count++; j++; } if(count==2 count==1) { for(k=0;k<=n;k++) a[k]=i; } } for(k=0;k<=n;k=k+1) printf("%d\t",a[k]); for(k=0;k<=n;k=k+2) sum+=a[k] * a[k]; printf("The sum of squares of alternative prime numbers is=%d",sum); getchar(); return 0; }
What is the Sum of natural even numbers?
The sum of the even numbers up to 2k, where k is an integer, is k(k + 1) = k2 + k
