(k x 4) + m = 4k + m
Just put the numbers together with the unknown for products, then put the other parts you need to add behind (think of grouping)
To write the sum of a number k and 7, you would use the mathematical expression k + 7. This expression represents adding the value of k to 7. In algebraic terms, this is known as an addition operation where k is the addend and 7 is the other addend. The result of this addition operation would give you the sum of k and 7.
x = ¼x^4 + 4x + k where k can be any number
1
It is simply: 6k
45
2(k+4)
k + 7
If A is a prime, then the answer is A^k where k is any positive integer.
No, the sum of four even numbers is not always a multiple of 4.. For example, 4 + 6 + 10 + 14 = 34 which is not a multiple of 4 If you include an "odd" number of even numbers which are not multiples of 4, then the total will not divide exactly by 4. In the above example 6 = 4 + 2, 10 = 4 + 4 + 2, and 14 = 4 + 4 + 4+ 2, and the total of the odd number of twos will not divide by 4 All multiples of 4 are the product of 2 with another even number: (Let a multiple of 4 be 4k. But 4 = 2 x 2, so 4k = (2 x 2)k = 2 x 2k and 2k is an even number for all k.) Let the four even numbers be 2k, 2m, 2n, 2p for some k, m, n, p. Then their sum is 2k + 2m + 2n + 2p = 2 (k + m + n + p) = 2q where q = k + m + n + p. k, m, n & p can be even or odd. If one, or three, of these is odd, then their sum, q, is odd. To be a multiple of 4 the sum k + m + n + p (= q) must be even. If it is odd, then twice it will not be a multiple of 4. For example, if k = 1, m = 2, n = 3, p = 5, then the four even numbers are 2 x 1 = 2, 2 x 2 = 4, 2 x 3 = 6, 2 x 5 = 10 and their sum is 2 x (1 + 2 + 3 + 5) = 2 x 11 = 22 which is not a multiple of 4.
enter the number whose digits are to be added num is the given value num=0! k=num%10 sum=sum=k k=num/10 num=k print the sum of the digits
To write the sum of a number k and 7, you would use the mathematical expression k + 7. This expression represents adding the value of k to 7. In algebraic terms, this is known as an addition operation where k is the addend and 7 is the other addend. The result of this addition operation would give you the sum of k and 7.
If the number of electrons in the M shell is equal to the sum of the electrons in the K and L shells, then the element is Silicon (atomic number 14). It has 4 electrons in the K shell, 8 in the L shell, and 2 in the M shell.
6 divided by the sum of 4 times x and 5 times k is equal to 6 times the reciprocal of (4x + 5k).
17
The sum of any two sides of a triangle is greater than the third side. So, 3+4>k, that is k<7 Also, 3+k>4 so that k>1 So 1 < k < 7
To find pairs of numbers in an array that add up to a value less than a given number k, you can use a two-pointer approach. Sort the array first, then use two pointers - one starting from the beginning and the other from the end. Check the sum of the two numbers pointed by the pointers. If the sum is less than k, increment the left pointer to increase the sum. If the sum is greater than or equal to k, decrement the right pointer to decrease the sum. Repeat this process until the pointers meet or the sum is less than k.
Let the number be k. According to the question the equation is; (3.5 * k) / 4 = 70 (3.5 * k) =280 k = 280 / 3.5 =80 Therefore the number is 80.