24x^2y^2
Set it equal to 0 and subtract x and solve for y
It is 8.
The coefficient is 6.
Log (x^3) = 3 log(x) Log of x to the third power is three times log of x.
x squared
2y4(16 - x4) = 2y4 (4 + x2)(4 - x2) = 2y4(4 + x2)(2 + x)(2 - x)
24x^2y^2
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
Set it equal to 0 and subtract x and solve for y
If you mean: 4x -3y = 1 and x -2y = 4 then the solutions are x = -2 and y = -3
fourth term of X-Y to the sixth power
To find the term from the end in the expansion of ( x - 12x^{3n} ), we can first rewrite it as ( x + (-12)x^{3n} ). The expansion of this expression will consist of two terms: ( x ) and ( -12x^{3n} ). The last term, which is the term from the end, is (-12x^{3n}). Therefore, the required term from the end is (-12x^{3n}).
6 ~
The coefficient is 6.
It is 8.
The coefficient is 6.
first quartile (Q1) : Total number of term(N)/4 = Nth term third quartile (Q3): 3 x (N)/4th term