6(3) - 2
18 - 2 = 16
6n -2
is the same as (6 x n) -2
and if n = 3, it would be
(6 x 3) -2
which if you use bidmas...
6 x 3 = 18 - 2 = 16
the answer is 16
6(3) - 2
= 18 - 2
= 16
6(3)-2
8-2
6
The pattern is Un = 6n2 - 7n + 1 = (6n - 1)*(n - 1) where n = 1, 2, 3, ...
n+6
Select a set of values for n. Usually, n takes the values 1, 2, 3, 4, ... In each case, calculate 4 times the value of n and then add 3. Each n and the associated value for 4n+3 form a row/column of the table.
what is the value of "N"? we can solve this equation when we know the value of N, once we know the value of N we just add 1 to it,
100
6n2
4 = -5n + 6n2 if you want to solve for n: 6n2 - 5n - 4 = 0 (3n - 4)(2n + 1) = 0 3n - 4 = 0, n = 4/3 2n + 1 = 0, n = -1/2 n = {-1/2, 4/3}
Composite. It is divisible by 3 for any n.
-8. The numbers can be generated by the following quadratic: t(n) = -6n2 + 23n - 4 for n = 1, 2, 3, ...
8 (again) The sequence is generated by t(n) = (-n3 + 6n2 + 7n - 12)/6 for n = 1, 2, 3, ...
6(n - 4)(n + 1) n = 4, -1
The pattern is Un = 6n2 - 7n + 1 = (6n - 1)*(n - 1) where n = 1, 2, 3, ...
3
That depends what the value of n is.
If you mean: -4*(n-6) = 12 then the value of n = 3
The value of the expression n(n-1)(n-2)(n-3)(n-4)(n-5) is the product of n, n-1, n-2, n-3, n-4, and n-5.
-2n +7 when n=3?