If you mean: -4*(n-6) = 12 then the value of n = 3
6n+3=15 6n+3-3=15-3=12 6n = 12 n=12/6 = 2
6n/10=3 6n=30 n=5
6n -3=2n+9 6n-2n=9+3 4n=12 n=12/4 n=3
The unknown variable in the expression: 6n+3 is n
5n + 3 = 14 - 6n <=> 5n +6n = 14 - 3 <=> 11n = 11 => n = 11/11 = 1
15/6n + 6/6n = 21/6n = 7/2n
-6n = 2 can be simplified giving the value of n as -1/3.
3 is called the constant term and the 6n is called the linear term.
I assume that you mean n = 3 6n + 4 = 6(3) + 4 = 18 + 4 = 22
6 normal, which for sulfuric acid is 3 molar.
All non-prime numbers are divisible by prime numbers. Now the smallest to prime numbers are 2 and 3. The next prime number is 5, which is 6*1 - 1. All larger numbers are in the form of one of 6n, 6n+1, 6n+2, 6n+3, 6n+4, 6n+5. Now 6n is divisible by 2 and so cannot be a prime. 6n+2 and 6n+4 are also divisible by 2 and so cannot be prime. 6n+3 is divisible by 3 and so cannot be prime. That leave 6n+1 and 6n+5 as the only two forms than can be prime. Note though that 6n+5 = 6m-1 where m = n+1. So all primes are of the form 2, 3, 6n+1 and 6n-1. And all primes can be divided by primes. The result follows.
6n - 4 - 3 = 3n + 10 + 4n -7 = 7n - 6n + 10 -17 = n