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How do you evaluate an algebraic expression?
You have to substitute a value for the letter variable in the expression. This is what we call evaluating the algebraic expression. An example would be 3x+1=7, when x=2.
If you have an equation of 12x plus 1 what is x?
Without an equality sign the given expression is not an equation and so therefore finding the value of x is not possible.
How do you solve x plus 1 over x?
You don't "solve" an expression. You can solve an equation; an expression can be simplified or otherwise manipulated, and if you know the value of "x" (in this case), you can evaluate its value.
What value of x makes the expression x undefined?
+1/0 or -1/0 or 0/0
Evaluate the expression for the given value of the variable 5y - 1 for y equals 3?
14
What is the answer for 3 over a plus 2 over a to the second power minus 1 over a to the third power?
a≠ 0,LCD = a33/a + 2/a2 - 1/a3= (3/a)(a2/a2) + (2/a2)(a/a) - 1/a3= 3a2/a3 + 2a/a3- 1/a3= (3a2 + 2a -1)/a3
Simplify the expression 2a -3 plus 4b - 2a -b -3 plus 5?
3b -1
What is 2a 3 4a-8?
They are 4 terms of an algebraic expression which does not have an equality sign in it.
What is the meaning of expression with variable?
It means that it is an expression, and it contains one or more variables. An "expression" is anything that can be calculated to obtain a number. For example, all of the following are expressions: 5 1 + 2 a a + 1 2a a + b
What is2a2 plus 5a plus 2?
As stated it is just an algebraic expression. However, if we equate it to zero then it can be solved. 2a2 + 5a + 2 = 0 This can be factored (2a + 1)(a + 2) = 0 This means that (2a + 1) = 0 or (a + 2) = 0 Then either 2a = -1 : a = -1/2 or a = -2
How do you factor the expression 8a minus 4?
32a + 8= 8(4a+1)
What is the expression and value of 1 to the power of 6?
The expression would be written as 16 The value of the expression is 1. 1 x 1 x 1 x 1 x 1 x 1 = 1
What is the multaplicative inverse of -2a?
The multiplicative inverse of -2a is 1/(-2a) = -1/2a
Factor a3 - 1?
(a - 1)(a^2 + a + 1)
Is it true When the base of an exponential expression is 1 the value of the expression always equals 1?
Yes.
Five terms of n-1?
an=an-1 To use this formula, you start of with a value on the first term, but theoretical, it'd turn out like this: a1=a1-1=a0 a2=a2-1=a1 a3=a3-1=a2 a4=a4-1=a3 a5=a5-1=a4 Where a0 would be your starting term (this formula is based on the previous term, and that's why you must have a value to start off with).
How do you solve -2a plus 5 equals 1?
-2a + 5 = 1 -2a = -5 + 1 -2a = -4 a = -4/-2 a = 2
