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You have to substitute a value for the letter variable in the expression. This is what we call evaluating the algebraic expression. An example would be 3x+1=7, when x=2.
Without an equality sign the given expression is not an equation and so therefore finding the value of x is not possible.
You don't "solve" an expression. You can solve an equation; an expression can be simplified or otherwise manipulated, and if you know the value of "x" (in this case), you can evaluate its value.
+1/0 or -1/0 or 0/0
14
a≠ 0,LCD = a33/a + 2/a2 - 1/a3= (3/a)(a2/a2) + (2/a2)(a/a) - 1/a3= 3a2/a3 + 2a/a3- 1/a3= (3a2 + 2a -1)/a3
3b -1
They are 4 terms of an algebraic expression which does not have an equality sign in it.
It means that it is an expression, and it contains one or more variables. An "expression" is anything that can be calculated to obtain a number. For example, all of the following are expressions: 5 1 + 2 a a + 1 2a a + b
As stated it is just an algebraic expression. However, if we equate it to zero then it can be solved. 2a2 + 5a + 2 = 0 This can be factored (2a + 1)(a + 2) = 0 This means that (2a + 1) = 0 or (a + 2) = 0 Then either 2a = -1 : a = -1/2 or a = -2
32a + 8= 8(4a+1)
The expression would be written as 16 The value of the expression is 1. 1 x 1 x 1 x 1 x 1 x 1 = 1
The multiplicative inverse of -2a is 1/(-2a) = -1/2a
(a - 1)(a^2 + a + 1)
Yes.
an=an-1 To use this formula, you start of with a value on the first term, but theoretical, it'd turn out like this: a1=a1-1=a0 a2=a2-1=a1 a3=a3-1=a2 a4=a4-1=a3 a5=a5-1=a4 Where a0 would be your starting term (this formula is based on the previous term, and that's why you must have a value to start off with).
20 = 1Consider what is the value of 2a ÷ 2a? Any number divided by itself is 1. Thus:2a ÷ 2a = 1The law of indices says that when dividing, they are subtracted, for example:25 ÷ 22 = (2 x 2 x 2 x 2 x 2) ÷ (2 x 2) = 2 x 2 x 2 = 23 = 25-2So 2a ÷ 2a is (also):2a ÷ 2a = 2a-a = 20Since any number subtracted from itself is 0 (= a - a). This must have the same value as before, thus:20 = 1The 2 above can be replaced by any number x which means that any number to the power 0 is 1:x0 = 1