Since the question is 3(2a), then just write it out. 3(2a) is 2a+2a+2a or 6a.
a-^2a-b^-a-b
The answer is 4a^2.
2a + 2b = c subtract 2a from both sides 2a - 2a + 2b = c - 2a 2b = c - 2a divide both sides by 2 (2/2)b = (c - 2a)/2 b = (c - 2a)/2 --------------------
3a-2a = 1
If the quadratic function is f(x) = ax^2 + bx + c then its inverse isf'(x) = [-b + +/- sqrt{b^2 - 4*(c - x)}]/(2a)
Since the question is 3(2a), then just write it out. 3(2a) is 2a+2a+2a or 6a.
2a+2a-7b+7b =4a
a-^2a-b^-a-b
The answer is 4a^2.
a + a + a - 2a = 3a - 2a = a
You divide 1 by the single number. For example, the multiplicative inverse of 5 is 1/5.If you are accustomed to fractions (the inverse of 2/3 is 3/2), consider the integer as the number divided by 1. In the above example, 5 = 5/1.You divide 1 by the single number. For example, the multiplicative inverse of 5 is 1/5.If you are accustomed to fractions (the inverse of 2/3 is 3/2), consider the integer as the number divided by 1. In the above example, 5 = 5/1.You divide 1 by the single number. For example, the multiplicative inverse of 5 is 1/5.If you are accustomed to fractions (the inverse of 2/3 is 3/2), consider the integer as the number divided by 1. In the above example, 5 = 5/1.You divide 1 by the single number. For example, the multiplicative inverse of 5 is 1/5.If you are accustomed to fractions (the inverse of 2/3 is 3/2), consider the integer as the number divided by 1. In the above example, 5 = 5/1.
2a + 2b = c subtract 2a from both sides 2a - 2a + 2b = c - 2a 2b = c - 2a divide both sides by 2 (2/2)b = (c - 2a)/2 b = (c - 2a)/2 --------------------
8b36
3a-2a = 1
9a +8 -2a -3 -5a = 2a +5
2a - 7 = -9 2a - 7 + 7 = -9 + 7 2a = -9 +7 2a = -2 2a/2 = -2/2 a = -2/2 a= -1