Without an equality sign and other information the details given can't be considered to be an equation.
10
You already know the value of x is 4. To solve the value of y = 64x, mutlply 64 x 4. Hence, y = 64*4 = 256.
Set up a system of equations. Let the numbers be x, y. X + Y = 153X = 5Y-11 Solve the first equation for Y.Y = 15-XPlug it into the second equation.3X = 5(15-X) - 11And solve for X.3X = 75 - 5X - 113X = 64 - 5X8X = 64X = 8 Plug X back into the original first equation.8 + Y = 15Y = 7 X = 8, Y = 7
Try elimination.4X + 13Y = 40- 1(4X + 3Y = - 40)4X + 13Y = 40- 4X - 3Y = 40-----------------------add10Y = 80Y = 8-------------find X ( top equation )4X + 13(8) = 404X + 104 = 404X = - 64X = - 16----------------------check in both equations for consistency4(- 16) + 13(8) = 40- 64 + 104 = 4040 = 40-------------top checks4(- 16) + 3(8) = - 40- 64 + 24 = - 40- 40 = - 40-------------------both check and are consistentSo, X is,- 16 ( while Y is 8 )
y=x^42-32x^2-x y' = 42x^41 - 32(2)x - 1 y' = 42x^41 -64x-1
8x to the second power times 3x to the second power (8x)2 + (3x)2 = 64x2 + 9x2 = 73x2 is one possibility, except the problem called for multiplication which would make the answer 64x squared times 9x squared = 576x to the fourth power It could also be read this way: 8x squared times 3x squared equals 24x to the fourth power. I wish my computer would do those cool little twos.
Divide both sides by 64 to find the value of x
64x = 37 Divide both sides by 64: x = 37/64 or 0.578125
4096
201.088
-x^6(64x^3 - 27)
320x2320x2320x2320x2
If you mean: 8x2-64x+120 = 0 then x = 3 or x = 5
8x - 6y = 184x - 6y = 6from the first equation:6y = 8x - 18substitute this value in the second equation:4x - (8x - 18) = 64x - 8x + 18 = 6-4x = 6 - 18-4x = -12x = 3Solve for y :8 x 3 - 6y = 1824 - 6y = 186y = 6y = 1
You already know the value of x is 4. To solve the value of y = 64x, mutlply 64 x 4. Hence, y = 64*4 = 256.
The GCF is 16x.
It is 64x^3
4. 12x^2-64x-256=4(3x^2-16x-64)