If the object is a square with sides of 3cm then the area is 0.0009 square metres.
We assume the pressure was measured on Earth's surface.
Weight (Newtons) = Pressure*area = (21 N/m2)*0.0009 m2 = 0.0189 Newtons.
The base area of 32 cm2 indicates the size, in terms of area, of the base of the object as 32 square centimetres. The height of 12 cm indicates that the perpendicular distance of the furtherst point of the object from the base is 12 centimetres.
Because Feck you, Goddamn cheating kids.
The answer depends on the object whose distance from Adrian is required.
Base 2 works like this: the first digit (from the right) is worth 1, next over is worth 2, next over is worth 4, and so on multiplying by 2 each time (Other bases work the same but multiply by whatever base it is, such as multiplying by 10 for base 10). So: 1=1 0=2 0=4 0=8 1=16 If it's a 1, you add it in, if it's a zero, you don't add it in. So, ignoring the zeros: 1=1 1=16 Add those up and get 17.
perimeter (P)=2(length+base) find length, area = length * base = (p/2-base)*base
The line of action of weight is outside the base of the body.
The weight and pressure is greater as the depth of water increases. The wide base is better able to withstand such forces. As the weight and pressure is less near the surface, the top of the dam wall doesn't need to be so wide.
You can't. In addition to the cylinder's diameter, the pressure at its base also depends on the density and depth of the fluid in the cylinder ... which gives you the weight of fluid resting on the base area. The pressure alone is not enough information to allow you to calculate the diameter.
[object Object]
You need to know how high the water column is to calculate the pressure it exerts at its base! For example, a column of water 1 metre deep would exert a pressure of 9.81 kPa at its base (density x gravity x depth - 1000 * 9.81 * 1). This would be equal to approx 1.42 PSI.
Dams must hold back water of a certain depth, determined by the height of the dam. The pressure exerted by this water on the dam is dependent in part by its depth, since the base of the dam must be able to hold pressures exerted by the weight of all the water above the base. Since the pressure is greater at the base, the dam is broader at the base.
The pressure that water exerts on the walls of the dam is proportional to the depth of the water or you might say the height of the column of water from the base of the dam. The hydraulic height is the same as the depth of the water to the bottom of the dam.
Assumptions:Density of water = 1000 kgm-3.Gravitational acceleration = 9.81 ms-2To calculate the pressure head of a 1 m depth of water, it is necessary to find the unit weight:Unit Weight = Density x gravityUnit Weight = 9810 Nm-3To calculate the pressure head at the base of the column of water:Pressure = Unit Weight x DepthPressure = 9810 x 1Pressure = 9810 PaThe resulting pressure is 9.81 kPa.
About non-living objects: all of them are subject to LOSS OF WEIGHT, more or less---depending upon their relative density with respect to that of water. An object Denser than water will sink into the water to the base of the contaniner. on the other hand, an object LIGHTER than water will float on the surface of the water. It will be in equlibrium under the action of two forces: namely downward weight W -------and upward upthrust or Buoyant force. Upthrust = weight of the liquid displaced due to immersion of the object Pressure due to liquid on the immersed object: liquid exerts pressure on immersed object, which increases LINEARLY with depth inside the water. Hence divers cannot dive into the sea beyuond a crictical depth becasue below that breathing is impossible and death may result due to SUFFUCATION For living Objects: aquatic life survives beneath the ICE-SHEET of ponds, rivers, seas etc due to ANOMALOUS EXPANSION OF THE WATER. iT IS ALSO due tto the fact that water is an INSULATOR of heat Also water DISSOVEs some OXYGEN for the aquatic life to sort of breathing. hope it pleases u
The Pressure is .434 times the height The FORCE takes a lot more calculations as the height and the weight of the water has to be calculated in plus the hydra-static pressure
Dams must hold back water of a certain depth, determined by the height of the dam. The pressure exerted by this water on the dam is dependent in part by its depth, since the base of the dam must be able to hold pressures exerted by the weight of all the water above the base. Since the pressure is greater at the base, the dam is broader at the base.
This is a simple physics question. The centre of gravity (the place where most of an object's weight is) does not fall outside the base of the mountain.