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What is the perimeter of a rectangle with 50 feet as the length and 4 feet as the width?
108 feet is the perimeter of a rectangle with a length of 50 feet and a width of 4 feet.
What is the length of a rectangle that has a perimeter of 108 feet the length is twice the width plus 6 feet what is the length?
P = 2L + 2WL = 2W + 62L = 4W + 12108 = 6W + 126W = 96W = 16L = 38 feet38 + 38 + 16 + 16 = 108
The width of a rectangle is 6 inches less than twice the length find the dimension of the rectangle if its area is 108 square inches?
Let the length of the rectangle be L and the width W, then W = 2L - 6 The area of a rectangle = L x W : 108 = L x (2L - 6) = 2L2 - 6L. Expressing this as a standard quadratic equation gives : 2L2 - 6L - 108 = 0. This can be factored as (2L + 12)(L - 9) = 0. As we are only concerned with positive solutions then the negative solution can be ignored, thus, When L - 9 = 0 then L = 9. As L = 9 then W = 2L - 6 = 18 - 6 = 12. The dimensions of the rectangle are : Width 12 inches, Length 9 inches.
The width of a rectangle is 6 inches less than twice its length Find the dimension of the rectangle if its area is 108 square inches?
Imagine a rectangle, the width is called 'Y' and the length is 'X'. the area is X * Y (because the area of a rectangle is the width and the length multiplied) we know the area is 108 so: XY = 108 http://wiki.answers.com/Q/The_width_of_a_rectangle_is_6_inches_less_than_twice_its_length_Find_the_dimension_of_the_rectangle_if_its_area_is_108_square_inches so basically : Y = 2X - 6 now do simultaneuos equations Y = 2X - 6 XY = 108 you can substitute Y from the first equation into the second one so X(2X - 6) = 108 (now multiply out the brackets by timesing everything inside the brackets (2X - 6) by everything out side the brackets (X)...) i cant do 2xsquared for some reason 2XX - 6X = 108 (simplofy by dividing the equation by two as it is divisble by two) XX - 3X = 54 move 54 to the other side by taking 54 away from both sides XX - 3X - 54 = 0 factorise (X - 9)(X + 6) = 0 now either X - 9 = 0 or X + 6 = 0 because to get the product of 0 you must mutiply it by 0 try both out X - 9 = 0 OR X + 6 = 0 add 9 to both sides subtract 6 from both sides X = 9 X = -6 so X is either 9 or -6 ---- but as we are talking about lengths, X has to be 9 because lengths can not be negative so X = 9 the equation from the begining Y = 2X - 6 will help as we now know X substitute X Y = 2(9) - 6= 18 - 6= 12 X (the length) = 9 Y (the width) = 12 wahey! you know the dimensions!Let the width be (2x+6) and the length be x:width*length = area(2x-6)*x = 108 sq inches2x2-6x-108 = 0Solving the above quadratic equation works out as:x = -6 or x = 9 it must be the latter because dimensions can't be negative.Therefore: width = 12 inches and length = 9 inchesCheck: 12*9 = 108 square inches
What is the length and width of a rectangle if the area is 108 square centimeters?
Without any further information regarding the rectangle, any two numbers that multiply to get 108 will suffice: 1cm x 108cm 2cm x 58cm 3cm x 36cm 4cm x 27cm 6cm x 18cm 9cm x 12cm Plus if the sides are allowed to not be whole numbers, there are many, many more. For example: 10cm x 10.8cm 5cm x 21.6cm
What is the perimeter of a rectangle with 50 feet as the length and 4 feet as the width?
108 feet is the perimeter of a rectangle with a length of 50 feet and a width of 4 feet.
What is a area of a rectangle with a length of 12 feet and a width of 9 feet?
108
What is the width of a rectangle with the length of 8 inches greater than its width find the width of the rectangle if its area is 108 square inches?
Let the width be x inches. So, the length will be 'x+8' inches. Area will be (x)*(x+8) sq. inches. This implies , (x)*(x+8) = 108 x2 + 8x - 108 = 0 Solve for x and you get the width.
The area of a rectangle is 108cm2 The ratio of the width to the length is 34 Find the length and the width?
The ratio of width to length is 34, so W = 34*L The area of a rectangle is L * W, so using the ratio we get L * 34*L = 108 cm2 34*L2 = 108 L = SQRT (108/34) = 1.78 cm W = 60.6 cm
What is the length of a rectangle that has a perimeter of 108 feet the length is twice the width plus 6 feet what is the length?
P = 2L + 2WL = 2W + 62L = 4W + 12108 = 6W + 126W = 96W = 16L = 38 feet38 + 38 + 16 + 16 = 108
The width of rectangle is 6 inches less tha twice its length Find the dimension of the rectangle if its area is 108 square inches?
W=12,l=9 ((9*2)-6=12, 12*9=108)
The length of a rectangle is three times its width If the perimeter of the rectangle is 48 inches what is its area?
Width = 'W'. Length = '3W'. Perimeter = 2 (Length + W) = 2 (3W + W) = 2 (4W) = 8W = 48 W = 6 inches and Length = 18inches Area = (Length) x W = 108 sq in============================ Easier way: Width = W, Length = 3W Area = (W) x (3W) = 3W2 We showed above that W = 6 3W2 = 3 x 36 = 108 in2
What is the area of a rug 12 feet long and 9 feet wide?
Assuming the rug is a rectangle, it 108 square feet (12 x 9 = 108) To get the area of any rectangle or square, you just need to multiply the length by the width.
If the length of a rectangle is 6 cm longer than twice the width and that the perimeter of the rectangle is 108 cm then what is the width and the length?
Suppose the width is w cm Then length is 2w + 6 cm So, the perimeter is 2l + 2w = 2*(2w + 6) + 2w = 4w + 12 + 2w = 6w + 12 Thus 6w + 12 = 108 so that 6w = 96 and then w = 16 cm And then, l = 2w + 6 = 32 + 6 = 38 cm
If the length of a rectangle is 3 times its width and if its area is 108 what is its perimeter?
Let the length be 3x and the width be x 3x*x = 108 square units. Which is the same as:3x2 =108 Dividing both sides of the equation by 3 gives: x2 = 36 Square rooting both sides of the equation gives: x = 6 So the length is 3*6 = 18 and the width = 6 Perimeter = 2*18+2*6 = 48 units.
The width of a rectangle is 6 inches less than twice the length find the dimension of the rectangle if its area is 108 square inches?
Let the length of the rectangle be L and the width W, then W = 2L - 6 The area of a rectangle = L x W : 108 = L x (2L - 6) = 2L2 - 6L. Expressing this as a standard quadratic equation gives : 2L2 - 6L - 108 = 0. This can be factored as (2L + 12)(L - 9) = 0. As we are only concerned with positive solutions then the negative solution can be ignored, thus, When L - 9 = 0 then L = 9. As L = 9 then W = 2L - 6 = 18 - 6 = 12. The dimensions of the rectangle are : Width 12 inches, Length 9 inches.
The length of a rectangle is 12ft longer than twice the width if the perimeter is 108 ft What is the length and the width?
Well, well, well, look who's trying to do some math! Let's cut to the chase - the width of the rectangle is 18ft and the length is 48ft. How did I figure that out? By using my fabulous brain and some good old algebra, honey.
