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What is the width and length of a rectangle with the perimiter of 108?
Wiki User
∙ 10y ago
Using whole numbers, there are 27 possibilities, including 1 x 53, 2 x 52, 3 x 51 and so on.
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∙ 10y ago
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What is the perimeter of a rectangle with 50 feet as the length and 4 feet as the width?
108 feet is the perimeter of a rectangle with a length of 50 feet and a width of 4 feet.
What is the length of a rectangle that has a perimeter of 108 feet the length is twice the width plus 6 feet what is the length?
P = 2L + 2WL = 2W + 62L = 4W + 12108 = 6W + 126W = 96W = 16L = 38 feet38 + 38 + 16 + 16 = 108
The width of a rectangle is 6 inches less than twice the length find the dimension of the rectangle if its area is 108 square inches?
Let the length of the rectangle be L and the width W, then W = 2L - 6 The area of a rectangle = L x W : 108 = L x (2L - 6) = 2L2 - 6L. Expressing this as a standard quadratic equation gives : 2L2 - 6L - 108 = 0. This can be factored as (2L + 12)(L - 9) = 0. As we are only concerned with positive solutions then the negative solution can be ignored, thus, When L - 9 = 0 then L = 9. As L = 9 then W = 2L - 6 = 18 - 6 = 12. The dimensions of the rectangle are : Width 12 inches, Length 9 inches.
The width of a rectangle is 6 inches less than twice its length Find the dimension of the rectangle if its area is 108 square inches?
Imagine a rectangle, the width is called 'Y' and the length is 'X'. the area is X * Y (because the area of a rectangle is the width and the length multiplied) we know the area is 108 so: XY = 108 http://wiki.answers.com/Q/The_width_of_a_rectangle_is_6_inches_less_than_twice_its_length_Find_the_dimension_of_the_rectangle_if_its_area_is_108_square_inches so basically : Y = 2X - 6 now do simultaneuos equations Y = 2X - 6 XY = 108 you can substitute Y from the first equation into the second one so X(2X - 6) = 108 (now multiply out the brackets by timesing everything inside the brackets (2X - 6) by everything out side the brackets (X)...) i cant do 2xsquared for some reason 2XX - 6X = 108 (simplofy by dividing the equation by two as it is divisble by two) XX - 3X = 54 move 54 to the other side by taking 54 away from both sides XX - 3X - 54 = 0 factorise (X - 9)(X + 6) = 0 now either X - 9 = 0 or X + 6 = 0 because to get the product of 0 you must mutiply it by 0 try both out X - 9 = 0 OR X + 6 = 0 add 9 to both sides subtract 6 from both sides X = 9 X = -6 so X is either 9 or -6 ---- but as we are talking about lengths, X has to be 9 because lengths can not be negative so X = 9 the equation from the begining Y = 2X - 6 will help as we now know X substitute X Y = 2(9) - 6= 18 - 6= 12 X (the length) = 9 Y (the width) = 12 wahey! you know the dimensions!Let the width be (2x+6) and the length be x:width*length = area(2x-6)*x = 108 sq inches2x2-6x-108 = 0Solving the above quadratic equation works out as:x = -6 or x = 9 it must be the latter because dimensions can't be negative.Therefore: width = 12 inches and length = 9 inchesCheck: 12*9 = 108 square inches
What is the length and width of a rectangle if the area is 108 square centimeters?
Without any further information regarding the rectangle, any two numbers that multiply to get 108 will suffice: 1cm x 108cm 2cm x 58cm 3cm x 36cm 4cm x 27cm 6cm x 18cm 9cm x 12cm Plus if the sides are allowed to not be whole numbers, there are many, many more. For example: 10cm x 10.8cm 5cm x 21.6cm
What is the perimeter of a rectangle with 50 feet as the length and 4 feet as the width?
108 feet is the perimeter of a rectangle with a length of 50 feet and a width of 4 feet.
What is a area of a rectangle with a length of 12 feet and a width of 9 feet?
108
What is the width of a rectangle with the length of 8 inches greater than its width find the width of the rectangle if its area is 108 square inches?
Let the width be x inches. So, the length will be 'x+8' inches. Area will be (x)*(x+8) sq. inches. This implies , (x)*(x+8) = 108 x2 + 8x - 108 = 0 Solve for x and you get the width.
The area of a rectangle is 108cm2 The ratio of the width to the length is 34 Find the length and the width?
The ratio of width to length is 34, so W = 34*L The area of a rectangle is L * W, so using the ratio we get L * 34*L = 108 cm2 34*L2 = 108 L = SQRT (108/34) = 1.78 cm W = 60.6 cm
What is the length of a rectangle that has a perimeter of 108 feet the length is twice the width plus 6 feet what is the length?
P = 2L + 2WL = 2W + 62L = 4W + 12108 = 6W + 126W = 96W = 16L = 38 feet38 + 38 + 16 + 16 = 108
The width of rectangle is 6 inches less tha twice its length Find the dimension of the rectangle if its area is 108 square inches?
W=12,l=9 ((9*2)-6=12, 12*9=108)
The length of a rectangle is three times its width If the perimeter of the rectangle is 48 inches what is its area?
Width = 'W'. Length = '3W'. Perimeter = 2 (Length + W) = 2 (3W + W) = 2 (4W) = 8W = 48 W = 6 inches and Length = 18inches Area = (Length) x W = 108 sq in============================ Easier way: Width = W, Length = 3W Area = (W) x (3W) = 3W2 We showed above that W = 6 3W2 = 3 x 36 = 108 in2
What is the area of a rug 12 feet long and 9 feet wide?
Assuming the rug is a rectangle, it 108 square feet (12 x 9 = 108) To get the area of any rectangle or square, you just need to multiply the length by the width.
The length of a rectangle is 12ft longer than twice the width if the perimeter is 108 ft What is the length and the width?
L = 12 + 2WL + W = 54(12 + 2W) + W = 5412 + 3W = 543W = 42W = 14L = (12 + 2W) = 40Perimeter = 2L + 2W = 28 + 80 = 108
If the length of a rectangle is 6 cm longer than twice the width and that the perimeter of the rectangle is 108 cm then what is the width and the length?
Suppose the width is w cm Then length is 2w + 6 cm So, the perimeter is 2l + 2w = 2*(2w + 6) + 2w = 4w + 12 + 2w = 6w + 12 Thus 6w + 12 = 108 so that 6w = 96 and then w = 16 cm And then, l = 2w + 6 = 32 + 6 = 38 cm
If the length of a rectangle is 3 times its width and if its area is 108 what is its perimeter?
Let the length be 3x and the width be x 3x*x = 108 square units. Which is the same as:3x2 =108 Dividing both sides of the equation by 3 gives: x2 = 36 Square rooting both sides of the equation gives: x = 6 So the length is 3*6 = 18 and the width = 6 Perimeter = 2*18+2*6 = 48 units.
The width of a rectangle is 6 inches less than twice the length find the dimension of the rectangle if its area is 108 square inches?
Let the length of the rectangle be L and the width W, then W = 2L - 6 The area of a rectangle = L x W : 108 = L x (2L - 6) = 2L2 - 6L. Expressing this as a standard quadratic equation gives : 2L2 - 6L - 108 = 0. This can be factored as (2L + 12)(L - 9) = 0. As we are only concerned with positive solutions then the negative solution can be ignored, thus, When L - 9 = 0 then L = 9. As L = 9 then W = 2L - 6 = 18 - 6 = 12. The dimensions of the rectangle are : Width 12 inches, Length 9 inches.
