Well, well, well, look who's trying to do some math! Let's cut to the chase - the width of the rectangle is 18ft and the length is 48ft. How did I figure that out? By using my fabulous brain and some good old algebra, honey.
If the width is 9' and the length is twice that, the length is 18'; the perimeter is twice the length plus twice the width, which is 36' + 18' = 54 feet.
Let the width of the rectangle be represented by "w" inches. Since the length is twice the width, it can be expressed as "2w" inches. The formula for the perimeter of a rectangle is P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Substituting the given values into the formula, we get 48 = 2(2w + w). Simplifying, we find that 48 = 6w. Solving for w, we find that the width of the rectangle is 8 inches, and the length is 16 inches.
If it's a rectangle, just minus the length from the perimeter twice and than divide what you have by 2. Width = (Perimeter - (length*2))/2
Given: p = 26cm and 2x width - 5cm = length p = 2(a+b) = 26cm; a+b = 13cm 2x6-5=7 The sides of the rectangle are: width 6cm and length 7cm
Designate the width by w. Then, from the problem statement, the length = 6 + 2w. The perimeter is twice the width plus twice the length, or: 2w + 2(2w + 6) = 36; or 2w + 4w + 12 = 36; or 6w = 24 or w = 4 meters; the length is 14 meters.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
The perimeter of a rectangle is twice the sum of the width and length: perimeter = 2 x (4.6in + 12.1 in) = 33.4 in
the width equals 14 cm. and the length equals 31 cm.
Area is length times width, perimeter is twice the sum of length and breadth.
The perimeter of a rectangle is 42. Meters. The length of the rectangle is threemeter less than twice the width.Mar
If you increase the rectangle's length by a value, its perimeter increases by twice that value. If you increase the rectangle's width by a value, its perimeter increases by twice that value. (A rectangle is defined by its length and width, and opposite sides of a rectangle are the same length. The lines always meet at their endpoints at 90° angles.)
156 It is impossible to calculate the area of a rectangle from its perimeter if no other dimension is known. The area of a rectangle is the product of its length and width, and the perimeter is twice the sum of its length and width.
Length = (Perimeter - twice width) / 2
Perimeter of a rectangle = twice (length + width), in this case 22 m.
The perimeter of any rectangle is twice the sum of the length and the width of the rectangle; in the present instance, 2(n + 2n) = 6n.
20 cm
12 meters