length*width = area 24.7*width = 550.81 Divide both sides by 24.7 to find the width: width = 22.3 meters
Let the width of rectangle is w cm (Length is 12 cm more) so length is w + 12 Perimeter = 16 times of width 2 (length + width) = 16 * width Rest of the homework, do yourself.
Length is 12ft, width is 4 ft. 2 x (length + width) = perimeter = 32 ft ⇒ length = 16ft - width [1] length x width = area = 48 sq ft Using [1] above: ⇒ (16ft - width) x width = 48 sq ft multiplying out and rearranging: ⇒ width2 - 16 x width + 48 = 0 factorizing: ⇒ (width - 4)x(width - 12) = 0 Thus width = 4 or 12, so using [1] above: ⇒ width = 4ft, length = 16 - 4 = 12ft or width = 12ft, length = 16 - 12 = 4ft Convention is that the length is larger than the width, thus rectangle is 12ft long by 4 ft wide.
Important to note are these formulae: Perimeter_of_rectangle = 2 x (length + width) Area_of_rectangle = length x width So if the perimeter and area are known, then: 2 x (length + width) = perimeter => length + width = perimeter / 2 => length = perimeter / 2 - width length x width = area => (perimeter / 2 - width) x width = area (substituting for length given above) => perimeter / 2 x width - width2 = area => width2 - perimeter / 2 x width + area = 0 which is a quadratic and can be solved either by factorization or by using the formula: width = (perimeter / 2 +/- sqrt(perimeter2 / 4 - 4 x area)) / 2 = (perimeter +/- sqrt(perimeter2 - 16 x area)) / 4 This will provide two values for the width. However, each of these values is the length for the other, so the larger value is the length and the smaller value is the width. Sometimes only 1 value will be found for the width above. In this case, the rectangle is actually a square which means that the length and width are both the same. Examples: 1. perimeter = 6, area = 2 width2 - perimeter / 2 x width + area = 0 => width2 - 6 / 2 x width + 2 = 0 => width2 - 3 x width + 2 = 0 => (width - 2) x (width - 1) = 0 => width = 2 or 1. So the length is 2 and the width is 1. 2. perimeter = 12, area = 9 width2 - perimeter / 2 x width + area = 0 => width2 - 12 / 2 x width + 9 = 0 => width2 - 6 x width + 9 = 0 => (width - 3)2 = 0 => width = 3 So the rectangle is a square with both length and width of 3.
perimeter 24 so length + width half of that ie 12. Length 3 times width must be 9 and width 3.
The area of the back yard is 216 square meters.
x2 + 13x
x2+13x
Your question is incomplete as written. If you meant a PERIMETER of 96 yards, then the backyard is 34 yards wide, 14 yards long.
In square feet. Multiply the length by the width.
Assuming the backyard is rectangular, the perimeter P = 2L+2W. Plugging in what we know, 121.2 = 2L + 2(25.4), we can solve L = 35.2. Multiplying the length by the width yields area = 25.4*35.2 = 894.08 square feet
Depends entirely on the length and width. If it's square then 40 feet, but otherwise just add the length and width and double your answer...
You multiply the width by the length to get the area. In this case the answer would be 288 square feet in the yard.
you need to find the dimensions of the backyard. if it's fencing, it's most likely going around 3 sides of your backyard (the 4th side is your house). so 2 times length, then add width.
Multiply length and width: 30 × 12 = 360 ft²
That's because a few countries are taking quite a while to adapt to international units. The correct unit for the length or width of a backyard would be the meter. The correct unit for its area would be the square meter.
160 meters. Width = 30 Length = 50 W+W+L+L = perimeter or Width x 2 + Length x 2 = Perimeter. 50 + 50 +30 +30 = 160