To find the answer you would do 161 divided by 14 because width plus length equals area. You just do the problem backwards.
the answer ends up being width=11.5cm
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Let the length be 2x and the width be x: Perimeter = 2(2x+x) = 84 4x+2x = 84 6x = 84 Divide both sides of the equation by 6 to find the value of x: x = 14 Therefore: length = 28cm and width = 14cm
Assuming that this is a rectangle, you know that the length (longer side) would be 7cm, and the width (shorter side) would be 6cm. The formula for perimeter is, 2(length) + 2(width) = Perimeter Now we can plug in our numbers, 2(7cm) + 2(6cm) = 14cm + 12cm = 26cm The perimeter would be 26cm, assuming that this is a rectangle ^^
Use Pythagoras' theorum a2 = b2 + c2 a2 = (9x9) + (12x12) 225 = 81 + 144 Ö225 = 15cm > 14cm. answer NO.
To check whether it is possible to have a triangle with side lengths 4cm, 13cm, and 14cm, we use a special rule.The rule is: If you take any two sides of a triangle and add their lengths, the sum of the lengths must be greater than the third side.Test this triangle. 4+13=17, which is bigger than 14. 14+4=18, which is bigger than 13. 13+14=27, which is greater than 4.The rule works for all side combinations, so it is possible to have a triangle like this.So the answer is: yes, you can have a triangle of side lengths 4cm, 13cm, 14cm. (Note that the lengths do not have to be in centimeters, for example they can be 4m, 13m, and 14m)