To solve an equation with two unknowns (x and y), you need two independent equations. answer -2x-2y=-12 -2(3)-2(3)=-12 -6-6+-12 so x=3, y=3
Any pair of numbers where the 'y' is 5 more than the 'x'. There are an infinite number of suitable pairs. 2y-2x=10 2y-2x+2x=10+2x 2y=2x+10 divide both side by 2. y=x+5
2x=3-y 2y=12-x y=3-2x 2(3-2x)=12-x 6-4x=12-x -3x=6 x=-2 2(-2)=3-y -4=3-y y=7 x=-2 y=7
If: 12 = 2y+x then y = -1/2x+6 So: y = 2x+4 and y = -1/2x+6 which means that they are perpendicular lines
The answer to x2 - 2x - 4y2 - 4y =(x - 2y)(x - 2y - 2)
-2x - 2y = -122x + 2y = 122y = 12 - 2xy = 6 - x
Factor out a 2; so it is 2(x+2y).
To solve an equation with two unknowns (x and y), you need two independent equations. answer -2x-2y=-12 -2(3)-2(3)=-12 -6-6+-12 so x=3, y=3
or x + y = 6 That cannot be simplified further and to solve for either variable will require another independent eqaution in x and y
Any pair of numbers where the 'y' is 5 more than the 'x'. There are an infinite number of suitable pairs. 2y-2x=10 2y-2x+2x=10+2x 2y=2x+10 divide both side by 2. y=x+5
2x+y=-12-4x-2y=30 x=-y/2+30, you plug this into -12-4x-2y=30 and get -12+2y-120-2y=30 which gives 2y-2y=162. This is not possible, so the equation is unsolvable.
2x=3-y 2y=12-x y=3-2x 2(3-2x)=12-x 6-4x=12-x -3x=6 x=-2 2(-2)=3-y -4=3-y y=7 x=-2 y=7
If: 12 = 2y+x then y = -1/2x+6 So: y = 2x+4 and y = -1/2x+6 which means that they are perpendicular lines
The result of the equation x + 2y - 2x - y equals x simplifies to y - x.
X + ( 2Y - 2X - Y ) is equal to Y - X
5
First get y in terms of x: 5x-2y=-12 ----- -2y=-12-5x ------ y=6+(5/2)x Sub into other equation: 2x+3y=-1 ---- 2x+3(6+(5/2)x)=-1 Solving for x gets: x= -2 Sub into other equation: 5x-2y= -12 --- 5(-2)-2y= -12 --- y=1 So x= -2, and y= 1