y = 3x - 4 or f(x) = 3x - 4 f(50) = 3(50) - 4 = 150 - 4 = 146 Thus, the y coordinate of the point is 146.
If you mean: 3x -y = 4 then y = 3x -4 whereas 3 is the slope and -4 is the y intercept
If you mean: 3x-y = 4 then y = 3x-4 and the y intercept is -4 with the slope being 3
To determine if the line passing through (-2, 4) and (5, d) is parallel to the graph of y = 3x + 4, we need to compare the slopes. The slope of the given line y = 3x + 4 is 3. The slope of the line passing through (-2, 4) and (5, d) can be calculated using the formula (y2 - y1) / (x2 - x1). So, (d - 4) / (5 - (-2)) = 3. Solving this equation will give you the value of d.
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y-3x-3 y=3x+3 A line with a slope of 3 crossing the y-axis at 3.
y=4/3x-4
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3x + 4y - 4 = 0 y = -2 3x + 4(-2) - 4 = 0 3x - 8 - 4 = 0 3x = 12 x = 4 (4,-2)
Get in function form. - 3X - Y = 4 - 1(- Y = 3X + 4) Y = - 3X - 4 ----------------------------solve for X and Y by the 0 out method - 3X - 4 = 0 - 3X = 4 X = - 4/3 --------------- Y = - 3(0) - 4 Y = - 4 -------------- Draw a line linking those points.
-3x + 4y = 12∴ 4y = 3x + 12∴ y = 3x/4 + 3So this is a line with a slope of 3/4, an x-intercept of {0, 3} and a y-intercept of {-4, 0}
y = 3x - 4 or f(x) = 3x - 4 f(50) = 3(50) - 4 = 150 - 4 = 146 Thus, the y coordinate of the point is 146.
3x - 4y = 1Subtract 3x from each side:-4y = -3x + 1Multiply each side by -1:4y = 3x - 1Divide each side by 4:y = 3/4 x - 1/4The graph is a straight line with [ slope = 3/4 ] and [ y-intercept = -1/4 ].
If you mean: 3x -y = 4 then y = 3x -4 whereas 3 is the slope and -4 is the y intercept
If you mean: 3x -y = 4 then y = 3x -4 whereas 3 is the slope and -4 is the y intercept
If you mean: 3x-y = 4 then y = 3x-4 and the y intercept is -4 with the slope being 3
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