(x-3)(3x+1)
(3x + 1)(x - 5)
(x + 2)(3x - 1)(3x + 1)
What is the question? Do you want to factor 3x2 -x -2? If that is the question the answer is (3x + 2)(x-1)
Substitute the point into the equation, eg. if you have point (1,2) and equation y=3x+7 you get 2=3*1+7 =10 2 doesnt equal 10, so (1,2) isn't on the graph y=3x+7
I think you mean (3x ± 1)^2 = (3x+1)(3x-1)?
If: 8-1/3x = 16 Then: x = -1/24
x = 1
5*2-3x-1 = 0 10-3x-1 = 0 -3x = 1-10 -3x = -9 x = 3
That factors to 3x(3x - 1)
(x-3)(3x+1)
(3x - 1)(3x + 1)
(3x + 1)(x - 5)
1
3x(6x - 1)
(x + 2)(3x - 1)(3x + 1)
x = 1 1/2 = [14 dividedby (6x - 2) ] - [6 dividedby (3x - 1) ]