y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
It is a straight line.
Yes.
That is slope-intercept form of a line.
y = (c - Ax) / (B)
y = 2x + 1.
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
It is a straight line.
Yes.
That is slope-intercept form of a line.
It cannot.
y = (c - Ax) / (B)
When the equation of a line is written in standard form: y = mx + c, the slope of the line is m. Here, y = 3x + 5 so slope = 3
Every point on the line has coordinates of the form (4, y) for different values of y. On a standrad coordinate graph, this will appear as a vertical line.
The equation of the line is written in the standard form, y = mx+c
y = 6/7x+3 General form of the line equation: 6x -7y+21 = 0