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They are two algebraic terms. Sadly, due to limitations of the browser that is used for posting questions on this site, there is no symbol between the two terms and so it is impossible to answer the question. Please try reposting using words such as "equals" or "is less than" etc.
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Where does the line intersect x equals 5 and x-2y equals 6?
x = 5 x-2y = 6 => x = 6+2y 6+2y = 5 2y = 5-6 2y = -1 y = -1/2 and x = 5 Point of intersection: (5, -1/2)
What is the answer to the equation (x - 2y = -2)?
4
How do you Substitute x equals y plus 3 into x plus 2y equals 9?
x = y+3 x+2y = 9 => x = 9-2y y+3 = 9-2y 2y+y = 9-3 3y = 6 y = 2 and x = 5
X-2y equals o 9y-4x equals 1 substitution method?
x - 2y=0 so x = 2y 9y - 4x=1 Substituting for x, 9y-4*(2y) = 1 or 9y-8y = 1 so that y = 1 then x = 2y = 2*1 = 2
What are the x and y values for 3x y3 and 2y-6x 6?
3x+2y+x
What is 3x-2y-x?
5
What is the solution-set for x-2y equals 0?
x-2y=0 x=2y The solution set is the set of all (x,y) such that x=2y
x−2y=−2?
x−2y=−2
How do you find the solution to x2-4y2 equals 16 and 2y-x equals 2?
x2 - 4y2 = 16∴ (x - 2y)(x + 2y) = 162y - x = 2∴ x = 2y - 2∴ ([2y - 2] - 2y)([2y - 2] + 2y) = 16∴ (y - 1 - y)(y - 1 + y) = 16∴ -1(2y - 1) = 16∴ 1 - 2y = 16∴ -2y = 15∴ y = -7.52y - x = -2∴ -15 - x = -2∴ x = -13So the point of intersection is (-13, -7.5)
Where does the line intersect x equals 5 and x-2y equals 6?
x = 5 x-2y = 6 => x = 6+2y 6+2y = 5 2y = 5-6 2y = -1 y = -1/2 and x = 5 Point of intersection: (5, -1/2)
X equals 2y-3 x equals 2y plus 4?
This means that 2y - 3 = 2y + 4 which is not possible.
X plus 2y equals 11 and x equals 14-2y?
x = 11 - 2y and 14 - 2y. This means that 11 = 14. Is there a typo in the question?
(x2 + 2y) (x3 - 2xy + y3)?
(x^2 + 2y)(x^3 - 2xy + y^3) = x^2(x^3 - 2xy + y^3) + 2y(x^3 - 2xy + y^3) Now, let's distribute each term: = x^2 * x^3 - x^2 * 2xy + x^2 * y^3 + 2y * x^3 - 2y * 2xy + 2y * y^3 Now, simplify each term: = x^5 - 2x^3y + x^2y^3 + 2x^3y - 4xy^2 + 2y^4 Now, combine like terms: = x^5 + x^2y^3 - 4xy^2 + 2y^4 So, the expanded form of (x^2 + 2y)(x^3 - 2xy + y^3) is x^5 + x^2y^3 - 4xy^2 + 2y^4.
How do you work out x plus 2y equals 7?
x+2y = 7 2y = -x+7 y = -0.5x+3.5
What are the coordinates of the x-intercept -x-2y equals 6?
solve for x -x-2y=6 -x=2y+6 x=-2y-6 plug in y=0 x=-6 when y is 0 therefore the x intercept is (-6,0)
2y x plus 2 equals?
2y(x+2)=
-2y equals x plus 8?
-2y=x+8 is the answer
