2(3x + 4) = 6x + 8 3(x - 5) = 3x - 15 6x + 8 - 3x + 15 = 3x + 23
2(3x + 4) = 6x + 8 3(x - 5) = 3x - 15 6x + 8 - 3x + 15 = 3x + 23
If the question is x + 4z - 5 - 3x when x = 2 and z = 3x, then First simplify the original statement x + 4z - 5 - 3x = 4z - 5 - 2x Secondly substitute in 3x for z 4z - 5 - 2x = 4*3x - 5 - 2x = 12x - 5 - 2x = 10x - 5 Lastly substitute 2 for the x 10x - 5 = 10*2 - 5 = 20 - 5 = 15 or x + 4z - 5 - 3x when x = 2 and z = 3x, so z = 3*2 = 6 x + 4z - 5 - 3x = 4z - 5 - 2x (replace the variables with the corresponding values) = 4*6 - 5 - 2*2 = 24 - 5 - 4 = 24 - 9 = 15
x=5
3x + 2x = 5x. 5x= (-4) X = (-4)/5 x= -0.8
3x/(5-x)/3=4 3x/(5-x)=4X3 3x=12(5-x) 3x=60-12x 3x+12x=60 x=4
x= 1.67(rnd) 5= -4+3x+4 5- -4= 9 9=3x+4 9-4=5 5=3x x= 1.67(rnd)
(x^2-2) (x^2+3x+5)= x^2(x^2+3x+5) -2(x^2+3x+5)= x^4 +3x^3 +5x^2 -2x^2 -6x -10= x^4 +3x^3 +3x^2 -6x -10
3x+4=10 To solve: 3x+4=10 3x=6 x=2
Simple algebra. 1 + 3x = -x - 4 3x = -x - 5 -3x = x + 5 -4x = 5 x = -1.25
2(3x + 4) = 6x + 8 3(x - 5) = 3x - 15 6x + 8 - 3x + 15 = 3x + 23
3x+4=-11 3x=-15 x=-5
2(3x + 4) = 6x + 8 3(x - 5) = 3x - 15 6x + 8 - 3x + 15 = 3x + 23
it means you multiply the number or variable by it self three times.For example,43 = 4*4*4 = 6453 = 5*5*5 = 125x3 = x*x*x3x3 = 3*x*x*x(3x)3 = 3x*3x*3x= 27x3
2x+5=3x+1 -x=-4 x=4
1 + 3x - x = x - 4 + 2x 1 + 4 = x + 2x - 3x + x 5 = x
2(3x + 4) = 6x + 8 3(x - 5) = 3x - 15 6x + 8 - 3x + 15 = 3x + 23