If the question is
x + 4z - 5 - 3x when x = 2 and z = 3x, then
First simplify the original statement
x + 4z - 5 - 3x = 4z - 5 - 2x
Secondly substitute in 3x for z
4z - 5 - 2x = 4*3x - 5 - 2x
= 12x - 5 - 2x
= 10x - 5
Lastly substitute 2 for the x
10x - 5 = 10*2 - 5
= 20 - 5
= 15
or
x + 4z - 5 - 3x when x = 2 and z = 3x, so z = 3*2 = 6
x + 4z - 5 - 3x
= 4z - 5 - 2x (replace the variables with the corresponding values)
= 4*6 - 5 - 2*2
= 24 - 5 - 4
= 24 - 9
= 15
x = 7 and 2/3
5=3x+2 3x+2-2=5-2 3x=3 ------ 3 x=1
y = 3x 3x + 4y = 30 3x + 4(3x) = 30 3x + 12x = 30 15x = 30 x = 2 y = 3x y = 3(2) y = 6 (2, 6)
3x+2 = 5x so 2x = 2 and hence x = 2/2 = 1
3x + 5x = 2x + 28x = 2x + 26x = 2x = (2/6) = 1/3
3x + 2 = 3x + 6 This is not possible.
(2, -1)
Their graphs are.
3x + 2 = 0 3x = -2 x = -2/3
4x plus 7 plus 3x equals 19 plus xx = 2
3x + 2 = -10 3x = -12 x = -4
x = 7 and 2/3
3x + 2 = Y
(-2, 4)
x + 2 = 3x-1 -2x = -3x = 1,5
x = 2
x3+3x2+3x+2 divided by x+2 equals x2+x+1