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Three times the product of twice a number y and x?
3(2y)(x)6xy
Where does the line intersect x equals 5 and x-2y equals 6?
x = 5 x-2y = 6 => x = 6+2y 6+2y = 5 2y = 5-6 2y = -1 y = -1/2 and x = 5 Point of intersection: (5, -1/2)
What is the answer to the equation (x - 2y = -2)?
4
How do you Substitute x equals y plus 3 into x plus 2y equals 9?
x = y+3 x+2y = 9 => x = 9-2y y+3 = 9-2y 2y+y = 9-3 3y = 6 y = 2 and x = 5
X-2y equals o 9y-4x equals 1 substitution method?
x - 2y=0 so x = 2y 9y - 4x=1 Substituting for x, 9y-4*(2y) = 1 or 9y-8y = 1 so that y = 1 then x = 2y = 2*1 = 2
How do you multiply 2x by 2y?
suppose u have a(x) and b(y)where a and b are constants , Multiplying a(x) by b(y) it's simply ab(xy) So if u have 2x by 2y this equals to 4xy or The answer is 4xy. 2x = 2 times x 2y = 2 times y 2 times x times 2 times y = 2 times 2 times x times y = 4xy
What is x plus 2y equals?
x + 2y = x + 2y Y and X aren't compatibles.
What is 3x-2y-x?
5
What is the solution-set for x-2y equals 0?
x-2y=0 x=2y The solution set is the set of all (x,y) such that x=2y
Three times the product of twice a number y and x?
3(2y)(x)6xy
What is 2 times the total of x plus y?
It is: 2*(x+y) or 2x+2y
How do you find the solution to x2-4y2 equals 16 and 2y-x equals 2?
x2 - 4y2 = 16∴ (x - 2y)(x + 2y) = 162y - x = 2∴ x = 2y - 2∴ ([2y - 2] - 2y)([2y - 2] + 2y) = 16∴ (y - 1 - y)(y - 1 + y) = 16∴ -1(2y - 1) = 16∴ 1 - 2y = 16∴ -2y = 15∴ y = -7.52y - x = -2∴ -15 - x = -2∴ x = -13So the point of intersection is (-13, -7.5)
Where does the line intersect x equals 5 and x-2y equals 6?
x = 5 x-2y = 6 => x = 6+2y 6+2y = 5 2y = 5-6 2y = -1 y = -1/2 and x = 5 Point of intersection: (5, -1/2)
X equals 2y-3 x equals 2y plus 4?
This means that 2y - 3 = 2y + 4 which is not possible.
X plus 2y equals 11 and x equals 14-2y?
x = 11 - 2y and 14 - 2y. This means that 11 = 14. Is there a typo in the question?
(x2 + 2y) (x3 - 2xy + y3)?
(x^2 + 2y)(x^3 - 2xy + y^3) = x^2(x^3 - 2xy + y^3) + 2y(x^3 - 2xy + y^3) Now, let's distribute each term: = x^2 * x^3 - x^2 * 2xy + x^2 * y^3 + 2y * x^3 - 2y * 2xy + 2y * y^3 Now, simplify each term: = x^5 - 2x^3y + x^2y^3 + 2x^3y - 4xy^2 + 2y^4 Now, combine like terms: = x^5 + x^2y^3 - 4xy^2 + 2y^4 So, the expanded form of (x^2 + 2y)(x^3 - 2xy + y^3) is x^5 + x^2y^3 - 4xy^2 + 2y^4.
How do you work out x plus 2y equals 7?
x+2y = 7 2y = -x+7 y = -0.5x+3.5
