3.597285024 is close but it is slightly above.
Xx = 100 thus X = 3.5973
4.6415888343 = 100
x=3
7.888609052 x 1069
Real power = voltage x current x power factor.
no, because xx=x squared, and x squared is not linear
The solution to this is: (xx)'= (elnx to the power of x)'= (exlnx)'= (xlnx)'*exlnx= [x(1/x) + 1(lnx)]*exlnx = (lnx+1)*exlnx= (lnx+1)*xx
xx or 2x.
it equals 1.637156443824977731300036754897665332 to the power of 49
10 to the second power (102) is the same as 10 x 10, which equals 100.
x=5 so it's 55+55= 110
100