x^0 = 1 for all x. The derivative of 1 is always zero.
e^(-2x) * -2 The derivative of e^F(x) is e^F(x) times the derivative of F(x)
the derivative of 1x would be 1 the derivative of x to the power of 1 would be 1. the derivative of x+1 would be 1 the derivative of x-1 would be 1 im not sure what you are asking, but however you put it, it's 1.
Your expression simplifies to just x^2 {with the restriction that x > 0}. The derivative of x^2 is 2*x
If the function is (ln x)2, then the chain rules gives us the derivative 2ln(x)/x, with the x in the denominator. If the function is ln (x2), then the chain rule gives us the derivative 2/x.
The derivative is 2x based on the power rule. Multiply the power by the coefficient of x then drop the power by one.
The first derivative of e to the x power is e to the power of x.
The derivative of ex is ex
2x is the first derivative of x2.
x^0 = 1 for all x. The derivative of 1 is always zero.
e^(-2x) * -2 The derivative of e^F(x) is e^F(x) times the derivative of F(x)
2x
the derivative of 1x would be 1 the derivative of x to the power of 1 would be 1. the derivative of x+1 would be 1 the derivative of x-1 would be 1 im not sure what you are asking, but however you put it, it's 1.
Your expression simplifies to just x^2 {with the restriction that x > 0}. The derivative of x^2 is 2*x
e^[ln(x^2)]=x^2, so your question is really, "What is the derivative of x^2," to which the answer is 2x.
1 divided by x to the third power equals x to the negative third. The derivative of x to the negative third is minus three x to the negative fourth.
well if you're finding the derivative with respect to x, it would be -tx^(-t-1)