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The solution to this is:

(xx)'=

(elnx to the power of x)'=

(exlnx)'=

(xlnx)'*exlnx=

[x(1/x) + 1(lnx)]*exlnx =

(lnx+1)*exlnx=

(lnx+1)*xx

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Q: What is the Derivative of x to the power of x?
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