Real power = voltage x current x power factor.
3
Yes. If the discriminant (of a quadratic equation) is...Positive: There are two real roots.Zero: There is a single "double" root. ("Double" means that if you factor, you will have a repeated factor.)Negative: There are two complex roots (and no real roots).
If you are looking to factor this expression, then it does not have a real solution.
True
It has one real solution.
power factor=real power/apparent power... real power in the sense the capacity of the circuit for performing a work in a particular time..for example the work done by a motor circuit is so and so...real power is what we consume from them... apparent power if the product of the current thro' the circuit and the voltage...it will be always greater than the real power.. if the POWER FACTOR IS 1.0(100%),THEN THE AC POWER IN THE CIRCUIT WILL BE EQUIVALENT TO THE POWER OFFERED BY A DC CIRCUIT....
Power factor is the cosine of a circuit's phase angle. A power factor of 0 (its lowest value), therefore, results from a circuit whose load current leads or lags the supply voltage by 90 degrees. In practise, this is unlikely to occur, as it requires either a purely-inductive or a purely-capacitive load and, real-life circuits have resistance.
P = V x I x pf
Power factor is defined as the ratio of real power over total power. Total power is the vector sum of real and reactive power.
An active power is the real component of the power of an alternating current circuit.
Power factor is the ratio of real power over total power, where total power includes the vector sum of real and reactive power. Resistors use real power. Perfect capacitors and inductors store power. In an AC system, capacitors and inductors will begin collecting power as the voltage applied to them increases, but eventually the voltage applied to them will be less than the charge they are already holding, and they will discharge into the circuit. This shows up as a phase shift in current relative to voltage.
0. Power factor has to do with the amount of real power. if you have a purely capacitive load, there is no real power flow, thus pf = 0. For purely resistive load, power factor will be 1.0.
The kVA (kilovolt ampere) is the vector sum of real + reactive power in an AC circuit. The kW (kilowatt) is a measure of the real power in that circuit. Inherently, a circuit will not require only real power, but also reactive power. Thus kVA is a more meaningful value when considering sizing equipment (such as transformers, bus work, breakers, etc.) because this equipment must be sized for the total current drawn, not just the real power usage.
If it's a simple resistive circuit, or a D.C. circuit, 1 kVA = 1 kW. Generally, it depends on your power factor. Since real power, P, is equal to the total power, S, multiplied by the power factor, p.f. Power factor is the cosine of the angle between the current and the voltage, O. So, P = S * cos(O)
If the power factor is 0.7 the reactive power equals the real power, so the capacitor should be 1.5 kVAr. That is a reasonable estimate for a small induction motor.
The ratio of active power (real power) and apparent power is called power factor ( pf ). Power Factor ( pf ) = Active Power / Apparent Power = .................. ( kvar )
This is 220 volts AC, I assume. 10 x 220 = 2.2kVA of power. The real power will depend on the power factor. Take the power factor times 2,200 to find the watts.