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If x+y = 3 and y times x = 2 then y = 1.
y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.
y = x + 2 y = -x + 4 x + 2 = -x + 4 2x + 2 = 4 2x = 2 x = 1 y = x + 2 y = 1 + 2 y = 3 (1, 3)
-6/y=5/-2 5y=12 y=12/5
The solution is: x = 1 and y = -1
If [ y = x + 2 ], then x is not -1 when y = 5.If [ y = x + 2 ],then when x = -1, y = 1,and when y = 5, x = 3.
x/y = 5/(y^2) and y/x = 5/(x^2). So x/y + y/x = 5/(y^2) + 5/(x^2), which equals 5x^2/(x^2 y^2) + 5y^2/(x^2 y^2) equals 5(x^2 + y^2)/25 equals (x^2 + y^2)/5. x^2 = 25/y^2, so you get (25/y^2 + y^4/y^2)/5 equals ((25 + y^4)/y^2)/25, which shows that your math teacher is on crack. Seriously, I'm not sure that's true.
y=2-x
x2 / y = (6)2 /2 = 36/2 = 18
-4
A pair of simultaneous eq;ns. 3x + y = 4 x + y = 0 Subtract the two eq'ns. This will eliminate 'y' 2x = 4 x = 2 Substitute this value of 'x' into either eq'n for 'y' 2 + y = 0 y = -2 or 3)2) + y = 4 6 + y = 4 y = 4 - 6 y = -2 ( again) . So the answer is ( x,y) = ( 2, -2).
Half correct because x = 2 and y = 6
X - Y = 2 When X = 3 you have 3 - Y = 2 Moving Y to RHS: 3 = Y + 2 Moving 2 to LHS: 1 = Y
If x+y = 3 and y times x = 2 then y = 1.
Yes if x=2 and y=2, then x=y
y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.
Y / (2+x)If x = -1 and y=2, thenY / (2+x) = 2/(2-1) = 2/1 = 2