-2x - 2y = -122x + 2y = 122y = 12 - 2xy = 6 - x
X squared = x+6 6+x=x squared X=6
no.. x equals 11
(x-y)2 is a square so (x-y)2 >= 0 expanding, x2 - 2xy + y2 >= 0 so x2 + y2 >= 2xy or 2xy <= x2 + y2
Assuming y' is dy/dx, y = x^4/4 + yx^2
2xy substitute 3 for y and 5 for x 2(5)(3) = 30
2xy=2*30*2=120
15xy-2xy-7x+x=13xy-6x
2xy + 6 = 4xyz Divide through by 2: xy + 3 = 2xyz 3 = 2xyz - xy = y*(2xz - x) Therefore, y = 3/(2xz - x) provided that 2xz - x is not zero.
(x, y) = (-6, 0)
No, it is not.
-2x - 2y = -122x + 2y = 122y = 12 - 2xy = 6 - x
The solution: x = 6/7 and x = -1
No because x = 2
you treat the letters like numbers i.e if x=4y, rearrange for y solution: divide both sides by 4 therefore y=1/4 x example 2: 6z+x/y = 2x-y rearrange for z solution: multiply both sides by y: 6z+x = y(2x-y) 6z+x = 2xy-y2 Take away x from both sides: 6z = 2xy-y2-x divide both sides by 6: z= 1/6(2xy-y2-x) done!
x=14
x2 + y2 = x2 - 2xy + y2 + 2xy = (x - y)2 + 2xy = 72 + 2*8 = 49 + 16 = 65 You could, instead, solve the two equations for x and y and substitute, but the above method is simpler.