The simplest example that fits that is y = x^2 - 7x + 12.
A math professor wouldn't like the process, but assuming we want a positive quadratic, and since positive quadratics are symmetrical along their minimums, we can skip some steps. We know that the local minimum is going to lie exactly between 3 and 4, at x = 7/2. Put everything on one side to get 2x - 7 = 0. Taking the integral (and skipping a few more steps) gets y = x^2 - 7x + c. Solving for c where y = 0 when x = 3, we find c = 12.
(x - 4)(x + 3) foil y = x^2 - x - 12 ----------------------
X = 3 A vertical line not having a Y intercept.
Answer t What is the slope of the line graphed below?his question…
3x+4y=-4 can be graphed on a graphing calculator or by changing the form of the equation from standard form to slope intercept form. Rearrange the equation 4y=-3x-4 divide by 4 y=(-3/4)x-1 Now, you can simply graph the equation using the y intercept and the slope of the equation. A good point to start with is (0,-1) you know this point is the y intercept because of the standard y intercept equation y= mx+b where b is the y intercept and m is the slope. From the y intercept of (0,-1) you can then graph using the slope which is the change of y over change in x. So you would move up 3 and to the left 4 since the slope is negative. You can also move down three and to the right 4. Then continue, this process until you have the equation graphed. It should be a straight line.
So, if we have the equation: F(x) = x^2 + 3 this is a function in terms of x, another way to look at this same problem is to write it as: y= x^2 +3. This function may be graphed if that is what you are looking for, the graph will be of a parabola and then the graph will be shifted from the origin up 3 from the origin.
(x - 4)(x + 3) foil y = x^2 - x - 12 ----------------------
They intercept at:no pointsone point onlytwo points.
You may mean, what is the graph of the function y = x^2 + 3. This graph shows a upward parabola with a y-intercept of 3 and a minimum at x=0.
we will select each options and find zeros (a)[tex] g(x)=x^2-4x-21 [/tex]for finding x-intercept , we can set g(x)=0and then we can solve for x[tex] g(x)=x^2-4x-21=0 [/tex]now, we can factor i…
Rose with 3 petals
X = 3 A vertical line not having a Y intercept.
12
To find the y-intercept of the function ( y = 3(6x) ), we need to evaluate it when ( x = 0 ). Substituting ( x = 0 ) into the function gives ( y = 3(6 \cdot 0) = 3(0) = 0 ). Therefore, the y-intercept is at the point (0, 0).
Yes, ( f(x) = x^2(4 - x) ) is a quadratic function. When expanded, it becomes ( f(x) = 4x^2 - x^3 ), which is a polynomial of degree 3. However, if we consider the term ( x^2(4 - x) ) without expansion, the leading term ( x^2 ) indicates it has a quadratic component, but the presence of ( -x^3 ) means it is not purely quadratic. Thus, it is a cubic function, not a quadratic one.
The given quadratic function can be rewritten in standard form as ( y = 2(x - 3)^2 + 5 ). The axis of symmetry for a quadratic function in the form ( y = a(x - h)^2 + k ) is given by the line ( x = h ). Here, ( h = 3 ), so the axis of symmetry is ( x = 3 ).
They are both polynomial functions. A quadratic is of order 2 while a cubic is of order 3. A cubic MUST have a real root, a quadratic need not.
When graphed, or written in the form [ y = f(x) ], the slope is -3 .