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The simplest example that fits that is y = x^2 - 7x + 12.

A math professor wouldn't like the process, but assuming we want a positive quadratic, and since positive quadratics are symmetrical along their minimums, we can skip some steps. We know that the local minimum is going to lie exactly between 3 and 4, at x = 7/2. Put everything on one side to get 2x - 7 = 0. Taking the integral (and skipping a few more steps) gets y = x^2 - 7x + c. Solving for c where y = 0 when x = 3, we find c = 12.

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