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The simplest example that fits that is y = x^2 - 7x + 12.
A math professor wouldn't like the process, but assuming we want a positive quadratic, and since positive quadratics are symmetrical along their minimums, we can skip some steps. We know that the local minimum is going to lie exactly between 3 and 4, at x = 7/2. Put everything on one side to get 2x - 7 = 0. Taking the integral (and skipping a few more steps) gets y = x^2 - 7x + c. Solving for c where y = 0 when x = 3, we find c = 12.
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Which quadratic function when graphed has x-intercept of 4 and -3?
(x - 4)(x + 3) foil y = x^2 - x - 12 ----------------------
Can a linear function does not have a y-intercept?
X = 3 A vertical line not having a Y intercept.
What is the slope of the line graphed below?
Answer t What is the slope of the line graphed below?his question…
How do you graph 3x plus 4y equals -4?
3x+4y=-4 can be graphed on a graphing calculator or by changing the form of the equation from standard form to slope intercept form. Rearrange the equation 4y=-3x-4 divide by 4 y=(-3/4)x-1 Now, you can simply graph the equation using the y intercept and the slope of the equation. A good point to start with is (0,-1) you know this point is the y intercept because of the standard y intercept equation y= mx+b where b is the y intercept and m is the slope. From the y intercept of (0,-1) you can then graph using the slope which is the change of y over change in x. So you would move up 3 and to the left 4 since the slope is negative. You can also move down three and to the right 4. Then continue, this process until you have the equation graphed. It should be a straight line.
Fx equals x2 plus 3?
So, if we have the equation: F(x) = x^2 + 3 this is a function in terms of x, another way to look at this same problem is to write it as: y= x^2 +3. This function may be graphed if that is what you are looking for, the graph will be of a parabola and then the graph will be shifted from the origin up 3 from the origin.
