-4
In order to find the slope of your line, we must first get it into y=mx+b.-9x-7y = 8-9x + 9x - 7y = 8- 7y = 9x + 8-7y/7 = 9x/7 + 8/7-y = 9x/7 + 8/7(-1) -y = 9x/7 + 8/7y = -9x/7 - 8/7The slope is -9/7 and the y-intercept is -8/7
-6
Points: (15, 8) and (7, 3) Slope: 5/8
If the slope is -3 and the point is (-8, -4) then (y - -4) = -3(x - - 8) => y = -3x -28
Convert the function into the general form y = mx + c, where 'm' is the slope. 2x + 4y = 8 : 4y = -2x + 8 : y = -x/2 + 2 : The slope is therefore -1/2.
Slope = coefficient of x = 8
This slope is 8
The slope is -2
Y = - 2X + 8 Just read it off the function, aY = mX + C - 2 = m(slope) 8 = Y intercept You can also zero out the variables in turn
y=-5x+8 the slope is -5.
8
It will have the same slope which is 2
y is equal to a constant, so the slope is zero.
3x + 2y = 8 2y=8-3x y=4-1.5x A quadratic has x^2 This is the equation of a line with negative slope.
-2 or written as a slope - 2/1
It is 2 and the y intercept is -8