(x - 4)(x + 3)
foil
y = x^2 - x - 12
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Answer t What is the slope of the line graphed below?his question…
So, if we have the equation: F(x) = x^2 + 3 this is a function in terms of x, another way to look at this same problem is to write it as: y= x^2 +3. This function may be graphed if that is what you are looking for, the graph will be of a parabola and then the graph will be shifted from the origin up 3 from the origin.
Whether or not a function has zeros depends on the domain over which it is defined.For example, the linear equation 2x = 3 has no zeros if the domain is the set of integers (whole numbers) but if you allow rational numbers then x = 1.5 is a zero.A quadratic function such as x^2 = 2 has no rational zeros, but it does have irrational zeros which are sqrt(2) and -sqrt(2).Similarly, a quadratic equation need not have real zeros. It will have zeros if the domain is extended to the complex field.In the coordinate plane, a quadratic without zeros will either be wholly above the horizontal axis or wholly below it.
The simplest example that fits that is y = x^2 - 7x + 12. A math professor wouldn't like the process, but assuming we want a positive quadratic, and since positive quadratics are symmetrical along their minimums, we can skip some steps. We know that the local minimum is going to lie exactly between 3 and 4, at x = 7/2. Put everything on one side to get 2x - 7 = 0. Taking the integral (and skipping a few more steps) gets y = x^2 - 7x + c. Solving for c where y = 0 when x = 3, we find c = 12.
x2 + 15x +36
Rose with 3 petals
The given quadratic function can be rewritten in standard form as ( y = 2(x - 3)^2 + 5 ). The axis of symmetry for a quadratic function in the form ( y = a(x - h)^2 + k ) is given by the line ( x = h ). Here, ( h = 3 ), so the axis of symmetry is ( x = 3 ).
They are both polynomial functions. A quadratic is of order 2 while a cubic is of order 3. A cubic MUST have a real root, a quadratic need not.
When graphed, or written in the form [ y = f(x) ], the slope is -3 .
To find the average rate of change of a quadratic function over an interval, you can use the formula: (\frac{f(b) - f(a)}{b - a}), where (a) and (b) are the endpoints of the interval. In this case, if the function is defined as (f(x)), you would calculate (f(5)) and (f(3)), subtract the two values, and then divide by (2) (which is (5 - 3)). The specific values will depend on the quadratic function provided.
It is y >= 5.
Answer t What is the slope of the line graphed below?his question…
I don’t know
They intercept at:no pointsone point onlytwo points.
The function ( f(x) = 2x^2 - 3 ) is a quadratic function, which is defined for all real numbers. Therefore, the domain of ( f(x) ) is ( (-\infty, \infty) ). This means you can input any real value for ( x ) into the function.
we will select each options and find zeros (a)[tex] g(x)=x^2-4x-21 [/tex]for finding x-intercept , we can set g(x)=0and then we can solve for x[tex] g(x)=x^2-4x-21=0 [/tex]now, we can factor i…
So, if we have the equation: F(x) = x^2 + 3 this is a function in terms of x, another way to look at this same problem is to write it as: y= x^2 +3. This function may be graphed if that is what you are looking for, the graph will be of a parabola and then the graph will be shifted from the origin up 3 from the origin.